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katen-ka-za [31]
3 years ago
13

Anna is preparing 30 days of dessert for her pet

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer:

I think it is 1.05 not a 100% sure through  

Step-by-step explanation:

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F(x) = 2 sin x- tanx is not a sinusoid.
OLga [1]

Answer:

True

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The length of a shadow of a building is
timofeeve [1]
H^2=x^2+y^2

35^2=29^2+y^2

y^2=35^2-29^2

y^2=384

y=√384

y≈19.60 m  (to the nearest hundredth of a meter, or nearest centimeter)

6 0
3 years ago
Compute the norm of v when v = (-8,7,4)​
dexar [7]

Answer:

the norm of V = =11.357816691601..

Step-by-step explanation:

\left\vert \overrightarrow{V} \right\vert  =\sqrt{\left( -8\right)^{2}  +\left( 7\right)^{2}  +\left( 4\right)^{2}  }

      =\sqrt{64+49+16}

      =\sqrt{129}

      =11.357816691601...

4 0
2 years ago
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
3 years ago
In our Solar system six of the eight planets have moons what percentage of the planets have moons
Vladimir79 [104]
75%
you just divide 6/8
7 0
3 years ago
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