Write an equation in slope intercept form for the line that passes through (-20,-6) with slope m=1/4

1 answer:

5 0

We start with the equation y-y1 =m (x-x1) because we have m the slope = 1/4 and a point on the line with the coordinates (x1=-20, y1=-6) so,

y+6=1/4 ( x+20);
y=(1/4)x + 20/4 -6;

y= (1/4)x -1 and this is the equation in slope intercept form y=mx +b where the lope m= 1/4 and b= -1 the y-intercept

Answer y= (1/4)x -1

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-2x + y = 0 -7x + 3y = 2

dsp73

This is a system of equations.
First, you set everything in terms of y.
Take the first equation and move set everything equal to y
y=0+2x
Since it’s 0, you don’t need to put it, so
y=2x works.
Then, you plug y=2x into the bottom equation, for the y.
-7x +3(2x)=2. You do this because now you have the same variable for both and it can be solved easily.
Then you can simplify.
-7x+3x = 2
Then combine like terms.
-4x = 2
Divide by -4 on each side.
x = -1/2
So, now that you have x, you can plug in your x-value back into the top equation.
-2(-1/2) + y = 0
Combine like terms
1+y=0
Get y by itself
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There you have it!
You can check by plugging in both values to any of the equations. We will use the top one here.
-2(-1/2) + (-1) =0
+1 + -1 = 0
It works!
So,
X= -1/2
Y= -1
Please rate me Brainliest answer :)

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Read 2 more answers

find the value of x2 values that separate the middle 90% from the rest of the distribution for 8 degrees of freedom

Anettt [7]

Answer:

With alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

Step-by-step explanation:

The significance level ∝ = 1- 0.9 = 0.1

But we need the area of the middle so we divide this significance level with 2

so that we get exactly the middle area .

Dividing 0.1/2= 0.05

So we will have two values for chi square

One with 0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.

So with alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

This can be shown with a graph.

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3 years ago

The answer to this word problem usinf discriminant

solniwko [45]

$\bf h=-9.8t^2+45t+1.2\implies 64.5=-9.8t^2+45t+1.2
\\\\\\
0=-9.8t^2+45t-63.3\\\\
-------------------------------$

$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic}
\\\\\\
0=\stackrel{\stackrel{a}{\downarrow }}{-9.8}t^2\stackrel{\stackrel{b}{\downarrow }}{+45}t\stackrel{\stackrel{c}{\downarrow }}{-63.3}
~~~~~~
\stackrel{discriminant}{b^2-4ac}=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}
\\\\\\
(45)^2-4(-9.8)(-63.3)\implies -456.36$

the discriminant is a negative value, thus no solution for such quadratic, meaning if we use h=64.5 like we did, there's no "t" seconds at which point the ball hits the batting cage.

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