C. 17 r 1 is the correct answer
Answer:
Time = 3secs
Max height = 56m
Step-by-step explanation:
Given the height reached by the rocket modeled by the equation;
h(x) = -5(x - 3)² + 56 where;
x is in seconds
The rocket velocity at its maximum height is zero.
Hence dh/dx = 0
dh/dx = 2(-5)(x-3)
dh/dx = -10(x-3)
Since dh/dx = 0
0 = -10(x-3)
0 = -10x + 30
10x = 30
x = 3secs
<em>Hence it takes 3 secs to reach the maximum height.</em>
Get the maximum height reached by the rocket. Substitute x = 3 into the equation given;
Recall that:
h(x) = -5(x - 3)² + 56
If x = 3
h(3) = -5(3 - 3)² + 56
h(3) = 0 + 56
h(3) = 56
<em>Hence the maximum height that the rocket reaches is 56m</em>
Answer:
The correct answer is A -3.
Step-by-step explanation:
18/(-3)=-6
To get to -6 from 18 you need to divide by -3.
To get to 2 from -6 you will divide by -3.
Answer: Mr Drysdale deposited 14,500
Step-by-step explanation:
Using the simple Interest formula
Simple Interest = Principal(Initial Money) * Interest Rate * Time Period
I = P*R*T
I = PRT
To get P which is the initial money he deposited, we divide both sides by RT
I/RT = PRT/RT
I/RT = P
Therefore the money deposited
P = I/RT
Interest (I)= 906.25
Interest Rate (R)= 6.25% = { converting percentage to decimal} (6.25/100)= 0.0625
Time Period (T) = 1 year
Principal (P)= ?
P= I/RT
P= 906.25/(0.0625 * 1)
P= 906.25/0.0625
P= 1450
The money he deposited in his local bank is 14,500
