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butalik [34]
3 years ago
6

If a car travel 96 km on 8 liters of gas, how much gas will be used if the car travels a distance of 120km?

Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:

10 liters

Step-by-step explanation:

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Step-by-step explanation:

200

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It is (0,0) there ya go :)
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3 lines are shown. A line with points C, A, F intersects a line with points B, A, E at point A. A line extends from point A to p
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Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi
miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

7 0
3 years ago
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Which expression is not equivalent to Negative 3 x minus one-half 4 y? 2 y minus 5 x minus one-half 2 y 2 x Negative 2 x minus o
Alona [7]

Answer:

The wrt=itten expressions are too difficult to interpret properly.  I did my best but I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>

Step-by-step explanation:

"Negative 3 x minus one-half 4 y"

-3x- (1/2)4y

<u>or -3x - 2y</u>

<u>=====</u>

The answer options are too garbled for me to make sense of them.  Are they:

1.  2 y minus 5 x minus one-half 2 y  :  2y -5x - (1/2)2y; <u>y -5x</u>  ?

2.  2 x Negative 2 x minus one-half 6 y :  2(-2x)- (1/2)6y; <u>-4x - 3y</u>  ?

3.  3 x Negative 3 x minus three-fourths 4 y :  3x(-3x) - (3/4)4y;  <u>-9x -3y</u>  ?

4.   one-fourth Negative 3 y minus three-fourths 7 y one-fourth minus 3 x:

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I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>

8 0
2 years ago
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