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babymother [125]
3 years ago
9

The quotient of 3 times a number n and 6 is 8. What is the value of n?

Mathematics
1 answer:
Fantom [35]3 years ago
7 0

Answer:

d

Step-by-step explanation:

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The model shows the addition expression 18 + 12.
Rashid [163]

Answer:

3(6+4) ._. hope this helps

3 0
4 years ago
Two farmers had a truck. The first farmer paid 4/5 of thr price, in the second paid the rest of his Farmer's share was 9600 what
alex41 [277]
9600 x 5 = 48000
Total price = 48,000
4 0
3 years ago
If AB=20, then AB+CD=?​
Leona [35]

Answer:

20*20+CD=400+CD

Step-by-step explanation:

Multiply  

20

by  

20

6 0
3 years ago
twin oaks soccer field is a rectangle. The longer side of the field is 108 yards long. The shorter side is 56 yards long. What i
Rus_ich [418]

Answer:

P = 328 yards

Step-by-step explanation:

formula is P= 2l + 2w

p  =  2(108) + 2(56) \\  = 216 + 112 \\  = 328  \: yards

5 0
2 years ago
A company developing a new cellular phone plan intends to market their new phone to customers who use text and social media ofte
Ber [7]

Answer:

A customer who sends 78 messages per day would be at 99.38th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average of 48 texts per day with a standard deviation of 12.

This means that \mu = 48, \sigma = 12

a. A customer who sends 78 messages per day would correspond to what percentile?

The percentile is the p-value of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 48}{12}

Z = 2.5

Z = 2.5 has a p-value of 0.9938.

0.9938*100% = 99.38%.

A customer who sends 78 messages per day would be at 99.38th percentile.

8 0
3 years ago
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