The drawing seems to suggest that angles BFA, AFE and EFD span a straight angle, just like angles BFC and CFD
This means that you have

But we know that both BFA and EFD measure 70 degrees, so the equation becomes
![[tex]70+AFE+70=180 \iff AFE + 140 = 180](https://tex.z-dn.net/?f=%20%5Btex%5D70%2BAFE%2B70%3D180%20%5Ciff%20AFE%20%2B%20140%20%3D%20180)
So, if you subtract 140 from both sides, you have

Answer:

Step-by-step explanation:
When choosing equations to write, make sure you choose a pair that allow you to isolate a variable and solve for it.
Sample solution:



Answer:
4
Step-by-step explanation:
54 x 40 = 2160 L
2160 ÷ 600 = 3.6 = 4
Answer:


Step-by-step explanation:

a) about the line y = 3
⇒
is the intersection point
So,

b) about the line x = 5
⇒ 
So,
![V = \int\limits^3_0\pi([5-0]^2-[5-y^2/9]^2)\:dy=\pi\int\limits^3_0(25-25+10y^2/9-y^4/81)\:dy=\\\\=\pi(10y^3/27-y^5/405)|^3_0=\pi(10-3/5)=\frac{47}{5} \pi](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5E3_0%5Cpi%28%5B5-0%5D%5E2-%5B5-y%5E2%2F9%5D%5E2%29%5C%3Ady%3D%5Cpi%5Cint%5Climits%5E3_0%2825-25%2B10y%5E2%2F9-y%5E4%2F81%29%5C%3Ady%3D%5C%5C%5C%5C%3D%5Cpi%2810y%5E3%2F27-y%5E5%2F405%29%7C%5E3_0%3D%5Cpi%2810-3%2F5%29%3D%5Cfrac%7B47%7D%7B5%7D%20%5Cpi)