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4 years ago

What are three ways in which clouds affect climate

1 answer:

6 0

Clouds affect climate in following way,
1. Clouds absorb sunlight coming from the sun which reduces the temperature in the atmosphere.
2. Clouds provide shade from the sunlight.
3. Heavy clouds can also bring rains.
4. Clouds can lower the climate temperature of a region.

Hope it helped. But that's what I knew.

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A backpack weighs 8.2 Newtons and has a mass of 5 kilograms on the moon what is the strength of gravity on the moon

lions [1.4K]

i dont get it so much but

The weight of the bag pack is 8.2 N. g = 1.64 m/s2. Hence, the acceleration due to gravity on moon is 1.64 m/s2. sooo? is it right

7 0

3 years ago

The US Environmental Protection Agency issues a daily report for pollution levels called the __________.

VARVARA [1.3K]

I think it’s D lol i’m not sure

5 0

4 years ago

Read 2 more answers

A ray of light is moving from a material having a high index of refraction into a material with a lower index of refraction.(a)

Sveta_85 [38]

(a) Away from the normal

The direction of bending of the ray of light can be found by using Snell's law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

n1, n2 are the index of refraction of the first and second medium, respectively

$\theta_1, \theta_2$ are the angle of the incident and refracted ray with respect to the normal to the surface, respectively

In this problem, the ray of light moves from a material with high index of refraction to a material with lower index, so:

$n_1 > n_2$

Re-arranging Snell's law we find

$sin \theta_2 = \frac{n_1}{n_2} sin \theta$

since

$\frac{n_1}{n_2}>1$

we also have

$sin \theta_2 > sin \theta_1\\\theta_2 > \theta_1$

so the ray of light bends away from the normal.

(b) The wavelength is greater in the second material (the one with lower index of refraction)

The wavelength of the light in a medium is given by

$\lambda=\frac{\lambda_0}{n}$

where

$\lambda_0$ is the wavelength of the light in a vacuum

n is the refractive index

We can rewrite the equation as

$\lambda_0 = \lambda_1 n_1 = \lambda_2 n_2$

And isolating $\lambda_2$ from the second equation

$\lambda_2 = \frac{n_1}{n_2} \lambda_1$

where

$\lambda_1 = 600 nm\\\frac{n_1}{n_2}>1$

So, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.

(c) The frequency is the same

While wavelength and speed of a light wave depend on the medium in which the wave is travelling through, the frequency does not depend on that, so it is exactly the same in the two mediums.

5 0

4 years ago

The distance between the earth and the sun is about 2.5x10¹¹m. Express SI prefix in kilometers

White raven [17]

Answer: 2.5x10^8 kilometers

Explanation:

Given that:

Distance between the earth and the sun = 2.5x10¹¹metres

Convert distance in metres to kilometers

Recall that 1000 metres = 1 kilometers

So, 2.5x10¹¹metres = Z kilometers

To get the value of Z, cross multiply

Z km x 1000 m = (2.5x10¹¹metres x 1km)

1000Z = 2.5 x 10^11

Divide both sides by Z

1000Z/1000 = 2.5 x 10^11/1000

Z = 2.5x10^8km

Thus, the distance between the earth and the sun is about 2.5x10^8km

6 0

3 years ago

Which of the following is true when an object of mass m moving on a horizontal frictionless surface hits and sticks to an object

vivado [14]

Answer:

C. The initial momentum should be equal to the final momentum due to the conservation of momentum.

$P_{initial} = mv_0\\P_{final} = (M+m)v_1\\v_1 = \frac{m}{M+m}v_0$

Since m/(M+m) < 1, v_1 > v_0.

Explanation:

Wrong -> A. Since the smaller particle still moves after the collision, it has a kinetic energy.

Wrong -> B. The total initial momentum is equal to the momentum of the smaller particle. Therefore, the momentum of the objects that stuck together is equal to that of the smaller object.

Wrong -> D. Since the bigger object is initially at rest and the surface is frictionless, the direction of motion will be the same as the direction of the smaller particle.

4 0

3 years ago