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GenaCL600 [577]
3 years ago
12

A car accelerates horizontally from rest on a level road at a constant acceleration of Down the road, it passes through two phot

ocells ("electric eyes" designated by 1 for the first one and 2 for the second one) that are separated by 20.0 m. The time interval to travel this 20.0-m distance as measured by the electric eyes is 1.40 as.
(a) Calculate the speed of the car as it passes each electric eye.
(b) How far is it from the start to the first electric eye
Physics
2 answers:
Neko [114]3 years ago
7 0

Answer:A is 14.2857

B is 20M

Explanation:(A)

the velocity or speed of a car is distance/time=20/1.4=14.2857

(B)

Distance between the two eye is 20m

11Alexandr11 [23.1K]3 years ago
5 0

Answer:i totally forgot how that works

Explanation:

??

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A stargazer has an astronomical telescope with an objective whose focal length is 195 cm and an eyepiece whose focal length is 1
Colt1911 [192]

Answer:

The best angular magnification is

-375

Explanation:

Fe = Fo - L

From the question, (Fo) = 1.08 cm while (L) = 0.56cm

Thus, Fe = 1.08 - 0.56 = 0.52cm

Now, let's apply the angular magnification equation ;

M = - Di/Do

Where Di is the distance from the lens to the image and Do is the distance of the object to the lens.

In this question, Di is represented by f which is the distance from the lens to the image and it is f= 195cm

Also,Do is represented by Fe which is 0.52cm and it is the distance of the object to the lens.

Thus m = - f/fe = - 195/0.52 = - 375

6 0
3 years ago
Se tiene un objeto a una altura de 8 m generando 450 J de energía potencial cuál es la masa de dicho objeto
fgiga [73]

Answer:

5.73kg

Explanation:

Given data

Height = 8m

Potential Energy = 450J

Required

The mass of the object

From the following expression

PE=mgh

we can substitute g= 9.81m/s^2 and the other parameters to get mass m

450= m*9.81*8

450= m* 78.48

m= 450/78.48

m= 5.73kg

Hence the mass is 5.73kg

8 0
3 years ago
g suppose a spring with spring constant of 50 N/m is hanging from the ceiling. You hang 2.0 kg mass from the spring. How far is
adelina 88 [10]

Answer:

The extension of the spring is 0.392 m.

Explanation:

Given;

spring constant, k = 50 N/m

mass attached to the spring, m = 2.0 kg

let the extension of the spring = x

The extension of the spring is calculated by applying Hook's law;

F = kx

mg = kx

x = \frac{mg}{k} \\\\x = \frac{2 \times 9.8}{50} \\\\x = 0.392 \ m

Therefore, the extension of the spring is 0.392 m.

8 0
3 years ago
justin and his friends are on the football team. they consider skateboarders at their school to be an out-group. what does this
laila [671]
A. They have negative feelings about the skateboarders. -apex
7 0
3 years ago
Read 2 more answers
If light has a speed of 122,000 mps in a transparent medium, what is the index of refraction of the medium? A. n = 1.52
castortr0y [4]

Answer:

A.\hspace{3}n=1.52

Explanation:

The refractive index of a medium is a measure to know how much the speed of light within the medium is reduced. It can be calculated with the next equation:

n=\frac{c}{v}   (1)

Where:

c=Speed\hspace{3}of\hspace{3}light\hspace{3}in\hspace{3}vacuum\\n=Refractive\hspace{3}index\\

v=Velocity\hspace{3}of\hspace{3}light\hspace{3}in\hspace{3}the\hspace{3}medium

The speed of light in the vacuum is approximately 300,000 km/s. In order to work with the same units let's do the proper conversion with the velocity of the medium:

122,000\frac{mi}{s} *\frac{1.60934km}{1mi}=196339.48\frac{km}{s}

Finally, replacing the data in (1):

n=\frac{300,000}{196339.48} =1.527965746\approx1.52

3 0
3 years ago
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