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GenaCL600 [577]
3 years ago
12

A car accelerates horizontally from rest on a level road at a constant acceleration of Down the road, it passes through two phot

ocells ("electric eyes" designated by 1 for the first one and 2 for the second one) that are separated by 20.0 m. The time interval to travel this 20.0-m distance as measured by the electric eyes is 1.40 as.
(a) Calculate the speed of the car as it passes each electric eye.
(b) How far is it from the start to the first electric eye
Physics
2 answers:
Neko [114]3 years ago
7 0

Answer:A is 14.2857

B is 20M

Explanation:(A)

the velocity or speed of a car is distance/time=20/1.4=14.2857

(B)

Distance between the two eye is 20m

11Alexandr11 [23.1K]3 years ago
5 0

Answer:i totally forgot how that works

Explanation:

??

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The distance is

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4 0
2 years ago
The electric motor of a model train accelerates the train from rest to 0.620 m/s in 21ms. The total mass of the train is 825 g.
Rudiy27

Explanation:

Average power = change in energy / change in time

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Explanation:

If the resistors are in parallel, the potential difference is the same for each resistor. But the total current is the sum of the currents that pass through each of the resistors. Then

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I = \frac{V}{R_1}+ \frac{V}{R_2} + ... + \frac{V}{R_N} = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)V = \frac{V}{R_T}

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R_T = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)^{-1} =\sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}

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