Work = force × distance, assuming that the force is parallel to displacement.
Work L=75×5=375J
Answer:
Charge of particle 2, 
Explanation:
Given that,
Charge 1, 
The distance between charges, r = 0.241 m
Force experienced by particle 1, F = 3.44 N
We need to find the magnitude of electric charge 2. It can be calculated using formula of electrostatic force. It is given by :




or

So, the magnitude of electric charge 2 is
. Since, the force is attractive then the magnitude of charge 2 must be negative.