So 9x<18 can be factored out into
9(x)<9(2)
you can divide both sides by 9
x<2
so the solution is any number more than 2, but not 2
To solve for x
bx=-7
divide b on both sides
x=-7/b
to solve for b
bx=-7
divide x on both sides
b=-7/x
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
Answer:
-4
7
-1
23
Step-by-step explanation:
I did the assignment on Edgenuity.
Answer:
the first option - 48s + 4.75
Step-by-step explanation:
