a) –a + b is negative
b) a – b is positive
c) b-a is negative
Step-by-step explanation:
1. Suppose a and b are real numbers where a > 0 and b < 0.
a. Is –a + b positive or negative. Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
–a + b
= -(6)+(-5) = -6-5 = -11
So, –a + b is negative
b. Is a – b positive or negative? Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
a - b
=6-(-5) = 6+5 = 11
So, a – b is positive
c. Is b – a positive or negative. Explain how you know
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
b-a
=(-5)-(6)
= -5-6
= -11
So, b-a is negative
Keywords: Solving Integers:
Learn more about solving integers at:
#learnwithBrainly
Answer:
1 = A 3 = b 4 = c
Step-by-step explanation:
I folded, trust me
Answer:
2a^4 / b^5
Step-by-step explanation:
(2a^2 / b) x ( a / b^2) ^2
= (2a^2 / b) x (a^2 / b^4)
= 2a^4 / b^5
(p.s if you are not gonna do it don't say "no thanks" and leech off this poor man's points)
10x(3x^2)
15x^2(2x)
5x(6x^2)
Answer:
1
1
0
0
Step-by-step explanation:
here´s and example for 1
1⁵
1x1x1x1x1=1
so 1 raised to the power of any number is 1
1 multiply by itself any number of times is 1
here´s an example for 0
0⁴
0x0x0x0=0
hence, the vale of 0 raised to any power is 0.
0 multiplied by itself any number of times is 0
