Volume of the cone = (1/3) pi r^2 h
h = 2r so substituting for h:-
V = (1/3) pi r^2 * 2r
V = (2/3) pi r^3
Explanation:
Perimeter of the park
= 337 m
= 33700 cm
Length of each fence panel
= 550 cm
Number of fence panel required
= Perimeter of the park/Length of each fence panel
= 33700 cm/550 cm
= 33700/550
= 3370/55
= 674/11
= 61 3/11
So, we will need 61 3/11 fence panels.
P.S. — 61 3/11 means 61 whole and 3/11. I have attached its picture, so that you understand.
1/2x2/4=1/4
2/4x3/6=1/4
3/6x1/2=1/4
One number is x
other number is 3x-10
x + 3x - 10 = 50
4x = 50 + 10
4x = 60
x = 60/4
x = 15 ← one number
the other number = 3x - 10 = 3*15 - 10 = 35
We have a sample that in fact represents the population.
We have to calculate the standard deviation of this population.
The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).
We have to start by calculating the mean of the population first:

Now, we can calculate the standard deviation as:
![\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%5B%5D%7B%5Cdfrac%7B1%7D%7Bn%7D%5Csum%5En_%7Bi%3D1%7D%5C%2C%20%28x_i-%5Cmu%29%5E2%7D)
![\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cdfrac%7B1%7D%7B6%7D%28%2837-34%29%5E2%2B%2838-34%29%5E2%2B%2839-34%29%5E2%2B%2840-34%29%5E2%2B%2839-34%29%5E2%2B%2811-34%29%5E2%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%283%5E2%2B4%5E2%2B5%5E2%2B6%5E2%2B5%5E2%2B%28-23%29%5E2%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%289%2B16%2B25%2B36%2B25%2B529%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%28640%29%7D%20%5C%5C%20%5Csigma%5Capprox%5Csqrt%5B%5D%7B106.67%7D%20%5C%5C%20%5Csigma%5Capprox10.33%20%5Cend%7Bgathered%7D)
Answer: the standard deviation of this population is approximately 10.33