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Alexxandr [17]
4 years ago
7

Find the exact solution of x. x2 = 16

Mathematics
2 answers:
vichka [17]4 years ago
5 0
The answer is x=16/2
x=8
Rama09 [41]4 years ago
3 0

Answer:

x=4

hope this helps! :D

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The height of a cone is two times its base diameter. What is the volume of the cone in terms of its base radius r?
nydimaria [60]

Volume of the cone = (1/3) pi r^2 h

h = 2r  so substituting for h:-

V = (1/3) pi r^2 * 2r

V = (2/3) pi r^3

5 0
3 years ago
your village community group is putting a new fence around the park .you offer to help and measure the distance around the park
makkiz [27]

Explanation:

Perimeter of the park

= 337 m

= 33700 cm

Length of each fence panel

= 550 cm

Number of fence panel required

= Perimeter of the park/Length of each fence panel

= 33700 cm/550 cm

= 33700/550

= 3370/55

= 674/11

= 61 3/11

So, we will need 61 3/11 fence panels.

P.S. — 61 3/11 means 61 whole and 3/11. I have attached its picture, so that you understand.

3 0
3 years ago
Name 3 different pairs of fractions that have the same product when multiplied
lana66690 [7]
1/2x2/4=1/4
2/4x3/6=1/4
3/6x1/2=1/4
8 0
4 years ago
The sum of two numbers is 50. One number is 10 less than three times the other number. What are the two numbers? 25 and 25 45 an
DENIUS [597]
One number is x
other number is 3x-10

x + 3x - 10 = 50
4x = 50 + 10
4x = 60
x = 60/4
x = 15   ← one number

 the other number = 3x - 10 = 3*15 - 10 = 35


6 0
4 years ago
All 6 members of a family work. Their hourly wages (in dollars) are the following.37, 38, 39, 40, 39, 11Assuming that these wage
tiny-mole [99]

We have a sample that in fact represents the population.

We have to calculate the standard deviation of this population.

The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).

We have to start by calculating the mean of the population first:

\begin{gathered} \mu=\dfrac{1}{n}\sum ^n_{i=1}\, x_i \\ \mu=\dfrac{1}{6}(37+38+39+40+39+11) \\ \mu=\dfrac{204}{6} \\ \mu=34 \end{gathered}

Now, we can calculate the standard deviation as:

\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}

Answer: the standard deviation of this population is approximately 10.33

3 0
2 years ago
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