First let P(x) = g(x)/f(x) = x^2 - 9 / 2 - x^0.5
The domain of the nominator is any value
The domain of the denominator is
Zeros of the denominator
2-x^0.5 = 0
-x^0.5 = -2
x^0.5 = 2
x = 4
domain of x^0.5 is x >= 0
(0,4) and (4, inf)
Answer: ME
Step-by-step explanation:
Answer:
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24∠-6x+12
-12 -12
12∠-6x
---- ----
-6 -6
x∠-2