Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Step-by-step explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Answer:
(-2.5, 1) and (0.5, 5)
Step-by-step explanation:
The main idea is to divide the line into four segments.
so you find the midpoint between (-4, -1) and (2, 7), which is (-1, 3).
then you find the midpoint again between (-4, -1) (-1, 3) and (2, 7) (-1, 3), which is (-2.5, 1) and (0.5, 5).
Isolate x on one side of the equation. divide by k.
2p over k =x-t
add t
(2p/k)+t = x.
hope this helps and have a wonderful day!
64 is the answer to your question
Is there a photo to attach to this? Number of hikers, number of fruit would be appreciated.
