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3 years ago

Help please!

Mathematics

1 answer:

Nookie1986 [14]3 years ago

5 0

Answer:

The height of the cone is 16 an the volume is 67.02 or rounded is 67

Step-by-step explanation:

All I did is use the formula to calculate the volume. I found out what the height was because the fraction has the height as the numerator.

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the diameter of a circle is 12yd. find the exact area and circumference of the circle. write your answers in terms of pie

Scorpion4ik [409]

So,

The area of a circle is $A = \pi *radius^{2} \\and\\Radius = Diameter \div 2\\\\So\\A = \pi * 6^2\\\\A = 36\pi$

For Circumfrence

$C = \pi * diameter\\C = 12\pi$

3 0

3 years ago

What is the surface area of the rectangular pyramid below?

Charra [1.4K]

Your answer would be 31.04 m2

3 0

2 years ago

Read 2 more answers

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Initial Knowledge Check

Cloud [144]

Answer:

I believe it would be five dollars since if you divide the price with the percentage yknow

5 0

2 years ago

A fruit market received a shipment of apples. The market sold them in bags with 14 apples in each bag. It sold 24 bags of apples

agasfer [191]

The answer is 462 apples was in the shipment or 33 bags!
1 bag = 14 apples
24 bags sold = 336 apples

126 apples was not sold = 9 bags

24 bags + 9 bags = 33 bags
33 bags * 14 apples/per bags = 462 apples

5 0

2 years ago

Read 2 more answers