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meriva
2 years ago
11

What is the justification for each step in solving the inequality?

Mathematics
1 answer:
Alik [6]2 years ago
4 0
75x+35≥7(11x+9)+475x+35≥7(11x+9)+4

75x+35≥77x+63+475x+35≥77x+63+4        [expand all blackets]

75x+35≥77x+6775x+35≥77x+67                [collect like terms]

−2x+35≥67−2x+35≥67 −2x≥32−2x≥32       [subtract 77x through]

x≤−16x≤−16                                                [subtract 35 through and divide through by 2]
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Simplify the radical expression. √45 + √20 - √5
viva [34]
√45 = √9√5 = 3√5
√20 = √4√5 = 2√5

3√5+2√5-√5=4√5

answer = 4√5
:)
5 0
3 years ago
20℅ of your employees work part time What fraction of the employees work part time
telo118 [61]
1/5
A fifth of your employees ..
4 0
3 years ago
Read 2 more answers
Please help I will give brainliest
Katyanochek1 [597]

Answer:

30 in^2

Step-by-step explanation:

The formula for finding the area of a trapezoid is A=a+b/2 x h

In this case, a=5, b=10, and h=4

When you input those values into the formula and solve for A, you get A=30

Please mark as brainliest ;)

3 0
1 year ago
grace rides her bike with a constant speed of 18 km/h how long will she take to travel a distance 72 kilometers
atroni [7]
If she rides her bike 18 km per hour
then it will take 4 hours to travel 72 km (72÷18)
the answer is 4
7 0
3 years ago
State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes
Sedbober [7]

Answer:

Maximum profit at (3,0) is $27.

Step-by-step explanation:

Let  quantity of  products A=x

Quantity  of products B=y

Product A takes time on machine L=2 hours

Product A takes time on machine M=2 hours

Product B takes time on machineL= 4 hours

Product B takes time on machine M=3 hours

Machine L can used total time= 8hours

Machine M can used total time= 6hours

Profit on product A= $9

Profit on product B=$7

According to question

Objective function Z=9x+7y

Constraints:

2x+3y\leq 6

2x+4y\leq 8

Where x\geq 0, y\geq 0

I equation 2x+3y\leq 6

I equation in inequality change into equality we get

2x+3y=6

Put x=0 then we get

y=2

If we put y=0 then we get

x= 3

Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I

Now put x=0 and y=0 in I equation in inequality

Then we get 0\leq 6

Hence, this equation is true then shaded regoin is  below the line .

Similarly , for II equation

First change inequality equation into equality equation

we get 2x+4y=8

Put x= 0 then we get

y=2

Put y=0 Then we get

x=4

Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II

Point  A and C are same

Put x=0 and y=0 in the in inequality equation II then we get

0\leq 8

Hence, this equation is true .Therefore, the shaded region is below the line.

By graph we can see both line intersect at the points A(0,2)

The feasible region is AOBA and bounded.

To find the value of objective function on points

A (0,2), O(0,0) and B(3,0)

Put A(0,2)

Z= 9\times 0+7\times 2=14

At point O(0,0)

Z=0

At point B(3,0)

Z=9\times3+7\times0=27

Hence maximum value of z= 27 at point B(3,0)

Therefore, the maximum profit is $27.

6 0
3 years ago
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