What can I conclude about these two circles

Is JH is the perpendicular bisector of GI what is GH?

soldi70 [24.7K]

Answer:

GH=12

Step-by-step explanation:

Definition of a perpendicular Bisector: a perpendicular bisector intersects another line segment at 90° and divides it into two equal parts.

Therefore it divides the line GI into two equal parts. That means that GH=HI and it was given that HI=12.

3 0

2 years ago

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

Lol I am having an exam ....no but help

mr Goodwill [35]

Answer:

3

Step-by-step explanation:

It should be 3 because when you look at it divide them all and each one gives you 3. If it's not then sorry.

4 0

3 years ago

What is the answer for 7/10-1/2 in simplest form

Musya8 [376]

Problem: 7/10 - 1/2
1/2 = x/10 Find the common denominator
1/2 = 5/10
Subtract the numerators
7-5
Answer: 2/10
Simplest form: 1/5

4 0

3 years ago

Read 2 more answers

Plz solve this question for me

sveticcg [70]

Answer:

2

Step-by-step explanation:

w + 1/2 ➡ (2w + 1)/2

w/4 + 2➡ (w + 8)/4

(2w + 1)/2 = (w + 8)/4

8w + 4 = 2w + 16 ➡ 6w = 12

w = 2

3 0

3 years ago

Read 2 more answers