Since the congruent angle is a right angle and it is not included, the two congruent sides of the triangles must include their hypotenuses and one of their legs.
The triangles would be congruent by the hypotenuse leg theorem, which states that if the hypotenuse and one leg of a right triangle is congruent to the hypotenuse and a leg of another right triangle, the triangles are congruent.
Answer:
hypotenuse leg theorem
The polynomial is not factorable, so use the quadratic formula.
y^2 + 8y + 19 = 0
x = (-b +- sqrt(b^2 - 4ac))/(2a)
x = (-8 +- sqrt(8^2 - 4(1)(19))/(2 * 1)
x = (-8 +- sqrt(64 - 76))/2
x = (-8 +- sqrt(-12))/2
If you have not learned imaginary/complex numbers, then the answer is "No solution" since there is no real number solution.
If you have learned imaginary/complex numbers, then we'll continue.
x = (-8 +- 2i sqrt(3))/2
x = -4 +- i sqrt(3)
I think it would be too confusing to type but it would look like this
