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Akimi4 [234]
3 years ago
15

What is the average mean of these scores 90 80 60 and 50

Mathematics
1 answer:
kirill115 [55]3 years ago
6 0

Answer:

70

Step-by-step explanation:

You add all the numbers together and then divided by the number of numbers so

90+80+60+50=

280 divided by 4 is 70

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Please solve this and show how you did. Thanks!!
kolbaska11 [484]
4x+6<-6
-6 -6
-------------
4x<-12

Then you divide 4x on both sides so 4x divided by 4x and -12 divided by 4x. When dividing this the 4 isnt a negative so you dont flip the "<" so it stays the same. The answer would be x<-3
5 0
3 years ago
Use your understanding of the constant of proportionality to determine k. If the relationship does not have a constant of propor
mihalych1998 [28]

Answer:

Far left: constant of proportionality= 3.4

Middle: q=12----COP=3

Far right: COP=4----not proportional

3 0
2 years ago
Read 2 more answers
What is the scintific notation of 4,497,000,000
Diano4ka-milaya [45]
4,497,000,000 = <span>4.497 x 10^9</span>
4 0
3 years ago
Read 2 more answers
The length of a rectangular fenced enclosure is 12 feet more than the width. If Farmer Dan has 100 feet of fencing, write an ine
Kitty [74]
Answer:
length = 31 ft
width = 19 ft

Explanation:
Assume that the width of the rectangle is w.
We are given that the length is 12 ft more than the width. This means that the length of the rectangle is w + 12

The perimeter of the rectangle in this case would be:
perimeter = 2 (length + width)
perimeter = 2 (12 + w + w)
perimeter = 24 + 4w

Assume that Dan would use all 100 ft of fencing to surround the yard. This would mean that the largest perimeter is 100 ft.

Therefore:
perimeter = 24 + 4w
100 = 24 + 4w
4w = 100 - 24
4w = 76
w = 19 ft

Since we have calculated that the width of the yard is 19 ft, we can substitute to get the length as follows:
length = 12 + w
length = 12 + 19
length = 31 ft

Hope this helps :)
7 0
4 years ago
Read 2 more answers
There are 6 fourth-grade students, 8 fifth-grade students, and 10 sixth-grade students on the girls’ soccer team at Truman Eleme
enyata [817]

Answer:

Your answer is

Fourth grade student = 25%

Fifth grade= 33.33%

Sixth grade= 41.67%

Want more answer then follow me, like and MARK MY ANSWER AS BRAINLIST ANSWER.

I need that urgently.

7 0
3 years ago
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