The period of a simple pendulum depends only on the length of the pendulum and the gravitational acceleration:
where L is the pendulum length and g the gravitational acceleration.
The problem says that Maya and the swing form a simple pendulum, so we can use this formula to calculate the period of Maya's motion, using the length of the swing (L=1.8 m):
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Answer: B=1.92nT
Explanation:This question uses the Biot-Savart law: the law is an equation that describes the magnetic field created by a current-carrying wire, and allows you to calculate its strength at various points.
B=(μ0/4*π)*q*v*r(unit vector)/r²
Also:
B=(μ0/4*π)*q*v*sin(θ)/r²
Where;
μ0 =permeability of free space = 4πx10-7 Hm-1
B = magnetic field in Tesla
V= velocity
r= radius
Therefore:
B=(4πx10-7/4*π)*q*v*sin(θ)/r^2
B=1x10-7*q*v*sin(θ)/r^2
Using:
q=15x10-3C
v=40m/s
tan(θ)=5/2 so θ=68.2°
r²=5²+2² (Pythagoras Theorem)
B can be calculated as:
B=1x10-7*15x10-3*40*sin(68.2)/(5²+2²)
B=1.92nT
Answer:
Option C
Explanation:
From the question we are told that:
Mass
Radius
Time
Generally the equation for Tension is mathematically given by
Therefore
, toward the center of the circle
Option C
D. Electrons are shared between the bromine atoms and carbon atoms
Explanation:
the answer to question one is complete the answer to question to is from negative to positive