Question

Max (15 kg) pushes Maya (12 kg) on a swing so that Maya moves in simple harmonic motion. The swing is 1.8 meters long and has a mass of 4 kg, concentrated in the seat. If Maya and the swing form a simple pendulum, what is the period of Maya’s motion?

Answer 1

The period of a simple pendulum depends only on the length of the pendulum and the gravitational acceleration:

where L is the pendulum length and g the gravitational acceleration.

The problem says that Maya and the swing form a simple pendulum, so we can use this formula to calculate the period of Maya's motion, using the length of the swing (L=1.8 m):

Read more on Brainly.com - brainly.com/question/9576569#readmore

Answer 2

Answer:

Time period, T = 2.7 s

Explanation:

Given that,

Mass of Max, m₁ = 15 kg

Mass of Maya, m₂ = 12 kg

Length of the swing, l = 1.8 m

Time period of the simple pendulum is :

$T=2\pi\sqrt{\dfrac{l}{g}}$

T is independent of the mass

So, $T=2\pi\sqrt{\dfrac{1.8\ m}{9.8\ m/s^2}}$

T = 2.7 s

So, the time period of Maya's motion is 2.7 s