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Taya2010 [7]
3 years ago
9

Solve and write solution in interval notation 4(x+1)+3>x-5

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer:

\large\boxed{x\in\left(-\dfrac{13}{3},\ \infty\right)}

Step-by-step explanation:

4(x+1)+4>x-5\qquad\text{use the distributive property}\\\\4x+4+4>x-5\\\\4x+8>x-5\qquad\text{subtract 8 from both sides}\\\\4x>x-13\qquad\text{subtract}\ x\ \text{from both sides}\\\\3x>-13\qquad\text{divide both sides by 3}\\\\x>-\dfrac{13}{3}\to x\in\left(-\dfrac{13}{3},\ \infty\right)

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Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
Which of the following is the parent function of all absolute value functions?
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F(x)=|x|

a parent function is the basic function before it has undergone transformations.
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How can i get the answer to 5 X 70 = 5 X ____ tens = ____ tens = _____
Maru [420]
Multiple 5x70 to get 350. Which makes the equation 350=5x and then you have to divide both sides by 5 to get x by itself.  so 5x/5 and 350/5 makes x=70
3 0
3 years ago
What is the Greatest Common Factor for 18;45
ira [324]
The GCF for 18 and 45 is 9.
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3 years ago
Find the LCM of k^2 + 3k + 2 and 2k^2 + 14k + 20.
Airida [17]

Answer:

  C.  2(k +2)(k +5)(k +1)

Step-by-step explanation:

The LCM will be the product of unique factors.

  (k^2 + 3k + 2)=(k+1)(k+2)\\(2k^2 + 14k + 20)=2(k+2)(k+5)

The unique factors are 2, (k+1), (k+2), (k+5), so the LCM is their product:

  2(k+1)(k+2)(k+5) . . . . matches choice C

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3 years ago
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