Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Short answer: 39
y = 7x - 3
f(x) = y = 7x - 3 Though there are some slight differences between f(x) and y, it is safe to say that f(x) acts (in this case) as a y value. So the question now is what does y(6) mean?
y(6) means exactly the same thing as what f(6) would mean. The both mean that where ever you see an x, put in a 6.
So y(6) means 7x - 3 = 7*6 - 3 = 39
Answer:
idk
Step-by-step explanation:
25a-5a
Hope this helps!!!!
Answer:
y = 1/2x + 2
Step-by-step explanation:
y = 1/2x + b
3 = 1/2(2) + b
3 = 1 + b
2 = b
