Step-by-step explanation:
<h3>#1)</h3>
As per the question, when the flow rate is negative, oil is moving into the small tank.
The large tank started with 600 gallons of oil. The recorded flow rate was - 4 gallons/ min.
That is, In one minute, 4 gallons of oil is moving from the large tank to the small tank.


Therefore, after 32 mins <u>1</u><u>2</u><u>8</u><u> </u><u>gals</u><u> </u><u>of</u><u> </u><u>oil</u><u> </u><u>has</u><u> </u><u>flown</u><u> </u><u>into</u><u> </u><u>the</u><u> </u><u>small</u><u> </u><u>tank</u><u>.</u>
<h3 /><h3> #2)</h3>
After 32 mins, the large tank lost 128 gallons of oil.
The remaining oil in the large tank = 600 - 128
=<u> 472 gallons </u>
Y+x=6
y=x^2-6x+6
You would have to expand the second one.
y=x*x-6x+6
and you add all of the x's
y=-6x^3+6
y+x=6
Solve the one that's in y=mx+b form.
And you should be able to solve it from there.
9ft shadow
Set up a proportion with height/shadow
8/18=4/x, cross multiply
8x=72
x=9
Answer:
22!
Step-by-step explanation:
Its just simple