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Serga [27]
2 years ago
10

Write log4 14 as a logarithm of base 3. HELP!!!!!

Mathematics
2 answers:
harkovskaia [24]2 years ago
8 0

Answer:

\log_414=\frac{\log_{3}14}{\log_{3}4}

Step-by-step explanation:

We have given  log_4 14 is given we need to convert it in logarithmic base 3

Using log base change property

\log_ab=\frac{\log_cb}{\log_ca}

So, here we have to change log_4 14  using log base change property with base 3

where, a=4,b=14 and c=3

Substituting these values in log base change property and we get

Therefore, log_4 14=\frac{\log_{3}14}{\log_{3}4}

Sonja [21]2 years ago
3 0
It would be log3 14/log3 4
Hope this helps. (:
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Answer:

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Step-by-step explanation:

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e. L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1} converges even s> 0.

f. L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4} converges to s> 0.

g. L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

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