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mihalych1998 [28]
3 years ago
10

Brooks Brother bought a suit that has a list price of 1219, with a chain discount of 7/4/2. What is the net price?

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0
1) 1219 - 1219x7% = 1133.67

2) 1133.67-1133.67x4% = 1088.32

3) 1088.32- 1088.32 x 2% = 1066.55
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Each side of a cube measures 5 cm in length. What is the cubes volume?
AysviL [449]

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Answer:

Your answer would be 125 cm³

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Step-by-step explanation:

In order to find the volume of a cube, we would need to use the right formula to find the volume for it.

Volume of a cube formula:

V = a^{3}

For our "a" value, we would need to plug in our side value, and for you case, the side value would be 5.

In a cube, all of the sides would be the same size, so you don't have to worry about using any different numbers.

Lets plug in 5 to our equation.

V = 5^{3}

Now we solve:

5^{3} = 125\\

This is also the same as:

5 *5*5 = 125

Your FINAL answer should be 125 cm³

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8 0
3 years ago
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Answer:

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If 4 is half of 8, and 50% is half of 100%, then 4:8 is an accurate ratio depecting that half the school owns a bike.

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2 years ago
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Explain how to check multiplication using addition and division ñ. Include an example in your explanation.
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EX 6.1 How many iterations will the following for loops execute? for (int i = 0; i < 20; i+ +) { } for (int i = 1; i <= 20
Romashka-Z-Leto [24]

Answer:

20, 20, 15, 20, 10, and 5 iterations respectively

Step-by-step explanation:

The loop "for (int i = 0; i < 20; i+ +)" starts at i=0 and increases the counter i by 1 at the end of each iteration. The counter must be less than 20, so the values of i in the loop are 0,1,2,3,...,19. These are 20 values, and thus the code iterated 20 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and increases the counter i by 1 at the end of each iteration. The counter can't exceed 20, so the values of i in the loop are 1,2,3,4,...,20. These are 20 values, and thus the code iterated 20 times.

Similarly, in "for (int i = 5; i < 20; i+ +)" i takes the 15 values are 5,6,7,...,19. Hence, the code iterated 15 times.

The loop "for (int i = 20; i > 0; i- -)" starts at i=20 and decreases the counter i by 1 at the end of each iteration, so the values of i in the loop are 20,19,18,...,1. These are 20 values, then we have 20 iterations.

The loop "for (int i = 1; i < 20; i = i + 2)" starts at i=1 and increases the counter i by 2 at the end of each iteration. The values of i in the loop are 1,3,5,7,...,19. These are 10 values, and thus the code iterated 10 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and multiplies the counter i by 2 at the end of each iteration, so the values of i in the loop are 1,2,4,8,16. Then we have 5 iterations.

6 0
3 years ago
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