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4 years ago

The prefix 'Kilo-' means a thousandth

Mathematics

1 answer:

vodka [1.7K]4 years ago

5 0

you answer will be 1.024 kg Hope this helps :D

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Enter your answer and show all the steps that you use to solve this problem.

slamgirl [31]

Answer:

h = -t+20

After 8 hours the candle will be 12 inches

Step-by-step explanation:

We have 2 points (time, inches)

(3,17) and (5,15)

We can find the slope

m = (y2-y1)/(x2-x1)

= (15-17)/(5-3)

= -2/2

= -1

We can use point slope form

y-y1 = m(x-x1)

Replace y with h and x with t

h-17 = -1 (t-3)

Distribute

h-17 = -t+3

Add 17 to each side

h-17+17 = -t+3+17

h = -t+20

3 0

3 years ago

Another find the equation of this line, please help meeee!

erma4kov [3.2K]

Answer:

y = 3/4x + 2

Step-by-step explanation:

to find the slope its rise over run and you go up 3 and run 4 to get 3/4. then you just look on the y axis and see that the line passes 2. so that is the answer

3 0

3 years ago

Solve for the unknown by using the additive inverse. Type the FULL answer in the box, without using any spaces (ex., X=5).

zavuch27 [327]

Answer:

X=16

Step-by-step explanation:

10x-8=9x+8

First you have to simplify.

10x-9x=1x

So now the equation looks like this

x-8=8

Now you have to get x by itself

-8+8=0 and we have to do the same thing on both sides of the equal sign 8+8=16

The equation now looks like this x=16

And that's your answer

3 0

3 years ago

0.77 the digit in the tens place is how many times is the value of the digit in the hundreds place

krek1111 [17]

*Tenths and *hundredths
The digit in the tenths place is 10 times the digit in the hundredths place. hope this helps.

4 0

3 years ago

The radius of a right circular cylinder is increasing at the rate of 3 ft/sec, while the height is decreasing at the rate of 6 f

goblinko [34]

Answer:

$\frac{dV}{dt}=-450\pi ft^3/sec$

Step-by-step explanation:

Let's assume

radius of cylinder as 'r'

height of cylinder as 'h'

so, we have

$\frac{dr}{dt} =3ft/sec$

$\frac{dh}{dt} =-6ft/sec$

r=15ft

h=10ft

now, we can use volume of cylinder formula

$V=\pi r^2h$

we can find derivative with respect to t

$\frac{dV}{dt}=2\pi r h\times\frac{dr}{dt} +\pi r^2\times \frac{dh}{dt}$

now, we can plug values

$\frac{dV}{dt}=2\pi (15)(10)\times3 +\pi (15)^2\times -6$

now, we can simplify it

$\frac{dV}{dt}=-450\pi ft^3/sec$

6 0

3 years ago