Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
you would have to add 3 to 1 cuz there is a one with the x and since 3 is negative that how you would get y=-3x+1
Step-by-step explanation:
Answer:
Okay so you jsut gotta divide
5/2 is basically saying 5 divided by 2, the bar basically means divide by.
Now 5/2 is 2.5
2.5 into a mixes is 2 1/2
<span>Neighbor: 2/5(x) </span>
<span>Remainder = x - 2/5(x) = 3/5(x) </span>
<span>Cousin = 4/9 * 3/5(x) = 4/15(x) </span>
<span>x - 2/5(x) - 4/15(x) = 15 </span>
<span>x - 6/15(x) - 4/15(x) = 15 </span>
<span>x - 10/15(x) = 15 </span>
<span>(15x - 10x) = 225 </span>
<span>5x = 225 </span>
<span>x = 225/5 = 45 </span>
<span>Therefore, he made 45 rolls</span>
