Whatever% of anything is just (whatever/100) * anything.
x = ounces of 14% iodine.
y = ounces of 29% iodine.
we know that in a 14% iodine solution, 14% is iodine and the rest is something else, we also know that "x" ounces of the solution have 14% of iodine, how much is that? (14/100) * x, or 0.14x.
likewise, in the 89 ounces of 47% solution there is (47/100) * 89 of iodine.
and likewise as well, in "y" ounces of 29% iodine there is (29/100) * y, or 0.29y of iodine.
bearing in mind that, whatever "x" and "y" may be, x + 89 = y, and that the sum of the iodine amounts also will equate 0.29y.
Answer:
my bad
Step-by-step explanation:
Answer:
If a person selected at random from this group is a man, there is a 31.25% probability that the person favors raising the drinking age.
Step-by-step explanation:
We have these following informations:
There are 1000 people in total.
540 favored raising the age. Of them 390 were female, and 540-390 = 150 were male.
460 were opposed. Of them, 130 were female and 460-130 = 330 were males.
If a person selected at random from this group is a man, what is the probability that the person favors raising the drinking age?
There are 150+330 = 480 males. Of them, 150 favors raising the drinking age.
So

If a person selected at random from this group is a man, there is a 31.25% probability that the person favors raising the drinking age.
Is there more to the question,
A and B, when dividing the two numbers for A, the answer is negative 4. And as for B, the answer comes out to negative 3 I believe. <span />