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skelet666 [1.2K]
4 years ago
14

In this arithmetic sequence the difference between each pair of consecutive terms is 1/2 Find the next term in the sequence expr

ess your answer in the lowest term
The chooses

2 1/5

2 7/10

1 2/7

1 7/10
Mathematics
1 answer:
Komok [63]4 years ago
8 0
So The last option I think ..
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Can someone give me the workings out for this one please
Elza [17]
50mph, 60 minutes, half both 25 and 30
A-B should be 30 minutes
B-C should probably be 20-25 personally I'd go with 25
so 55?
5 0
3 years ago
write an equation to represent the total cost for a certain number of cans. Use "c" for cost and "n" for number of cans​
Allushta [10]

Answer:

C(n)=1.25n

Where n= number of cans

Step-by-step explanation:

C=cost

n=number of cans

Quantity Total cost

1 $1.25

2 $2.50

3 $3.75

4 $5.00

Total cost, c(n) =1.25n

Check

Total cost when n=4

Total cost c(4)=1.25×4

Total cost c(4)=5.00

8 0
3 years ago
Trigonometric identities assignment 4
kykrilka [37]

Answer:

<em>Answer: choice D.</em>

Step-by-step explanation:

<u>Trigonometric Functions</u>

We need to recall some properties and definitions of the trigonometric functions.

\displaystyle \tan \theta=\frac{\sin\theta}{\cos\theta}

\displaystyle \sec \theta=\frac{1}{\cos\theta}

We need to simplify the following expression:

5\sin\theta\sec\theta

Substituting the identity for the secant:

\displaystyle 5\sin\theta\sec\theta=5\sin\theta.\frac{1}{\cos\theta}

Operating:

\displaystyle 5\sin\theta\sec\theta=5\frac{\sin\theta}{\cos\theta}

Substituting the definition of the tangent:

\displaystyle 5\sin\theta\sec\theta=5\tan\theta

Correct choice D.

6 0
3 years ago
Centimeters and meters size of window
Gnom [1K]

Answer:

Tiff, hon, just measure a window, your wasting your time

Step-by-step explanation:

7 0
4 years ago
The mean age of Mr Jasmi,Miss Haslinda and their three children is 38 years. The mean age of their three children is 18 years. C
DedPeter [7]
Answer: 68

Explanation:

Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children

We can write:
(x + y + a + b + c)/5 = 38

But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54

Substitute this value to our first equation

(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136

Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2

But x + y = 136

=> mean age = 136/2 = 68
4 0
3 years ago
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