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Lelechka [254]
3 years ago
5

I need help with 17&18!!!

Mathematics
1 answer:
AlekseyPX3 years ago
4 0

17. the answer is b

18. i don't know

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Pls help me with trig :)
trapecia [35]

Answer:

Step-by-step explanation:

let ∠GEF=x

then ∠GFE=90-x

\frac{GH}{EH}=tan x\\GH=EH~ tan x\\or~ GH=a ~tan x=6 tan x\\\frac{GH}{FH}=tan (90-x)=cot x\\GH=FH*cot x\\GH=b*cot x=27 cot x\\6 tan x=27 cotx\\\frac{tan x}{cot x}=\frac{27}{6}\\tan ^2 x=\frac{27}{6}=\frac{9}{2}\\sec^2x-tan^2x=1\\sec^2 x=1+tan ^2x=1+\frac{9}{2}=\frac{11}{2}\\\frac{EG}{EH}=sec x\\ EG=EH sec x=a sec x= 6 sec x=6\sqrt{\frac{11}{2} } =3\sqrt{22} \approx 14.07

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3 years ago
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Mrac [35]

You need to provide a screenshot or recreation of the rest of the problem's information.

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3 years ago
Find the missing side of this right
navik [9.2K]

Answer:

x = 13

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First start with the blank equation

a^{2} + b^{2} = c^{2}

Plug in the legs and hypotenuse. Remember c squared is always the hypotenuse.

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3 slices

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3 0
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