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astraxan [27]
3 years ago
14

If Jose's present age is 3n, how old will he be in 5 years?

Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer:

3n + 5

Step-by-step explanation:

You can't add 5 to 3n. So in 5 years he will 3n + 5.

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Let f(x) = ............
34kurt

Answer:

So first lets find g(-1)

so we plug in the answers:

-2 * -1 ^2 -4

-2*1-4 = -2-4 =

-6

Now lets solve for f(-2)

-2^2-3

4-3=1

-6+1 = 5

3*5 = 15

Im getting answer of 15 but it shows -15 or something, so I dont know if I got it wrong or if its like a dash then the answer.

3 0
3 years ago
A helicopter is hovering 110 feet in the air over a landing pad. If a man sees the helecopter at an angle of elevation of 29°, w
Pavel [41]
See the attached figure to better understand the problem

we know that

tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft 
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft

the answer is
the man is  198.45 ft  from the helicopter landing pad 

3 0
3 years ago
Oh lord help :,) please and thank you
ziro4ka [17]

Answer:

The answer is 19.10 $

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
what is the equation in point-slope form of the line that passes through the point ( -1,,-4) has a slop of a -3​
Vesnalui [34]
The answer has to resemble y=Mx+b so to find your y intercept plug in your coordinates into that equation so put your slope in for m and your x intercept in for x and the y intercept in for y so -4= -3(-1)+b now get b alone -1=b so your equation would be y=-3x-1
6 0
3 years ago
A sphere with a diameter of 5 feet long is being painted. how much more paint would be needed to paint a sphere that has four ti
MArishka [77]

well, if the diameter is 5, thus its radius must be half that, or 2.5, and therefore, the radius of the one four times as much will be (4)(2.5).

Let's simply get their difference, since that'd be how much more is needed from the smaller to larger sphere.

~\hfill \stackrel{\textit{surface area of a sphere}}{SA=4\pi r^2}\qquad \qquad r=radius~\hfill \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\large difference of their areas}}{\stackrel{\textit{radius of (4)(2.5)}}{4\pi (4)(2.5)^2}~~ - ~~\stackrel{\textit{radius of 2.5}}{4\pi (2.5)^2}}\implies 100\pi -25\pi \implies 75\pi ~~ \approx ~~235.62~ft^2

8 0
2 years ago
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