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3 years ago

Write sentence as inequality. Plz help A number x is less than 5 and greater than 3.

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

4 0

Answer:

3<x<5

Step-by-step explanation:

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HELP PLS ASAP

8090 [49]

Answer:

D. x=(1/6)y^2

Step-by-step explanation:

D. x=(1/6)y^2

3 0

2 years ago

carmen participated in a read-a-thon.MR.cole pledge $4.00 per book and gave carmen $44.00.How many books did carmen read

finlep [7]

Answer:

11 books

Step-by-step explanation:

because if she gets $4 per book and gets $44 in total then that means she has read 11 books because 4 times 11 is 44.

4 0

4 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago

This is for middle school 9th grade please help me :)

Stolb23 [73]

Answer:

i think it's undefined

Step-by-step explanation:

7 0

3 years ago

Troy sold 28 bags of popcorn and 40 candy bars and made $282. Jake sold 17 bags of popcorn and 20 bags of candy and made $160.50

Ghella [55]

One bag of popcorn would cost $6.50

To solve this, we can set up equations:
28p+40c=$282
17p+20c=$160.50

To solve this system, we would need to make either the candy bars the same or the bags of popcorn the same. Since we are solving for bags of popcorn, we will make the candy bars the same:
20(28p+40c=$282)
40(17p+20c=$160.50)

Which would give you:
560p+800c=$5,640
680p+800c=$6,420

Subtract them:
(680p+800c=$6,420)
-(560p+800c=$5,640)
_________________
120p=$780

Now divide by 120 to get the price of one bag of popcorn:
120p=$780
_________
120

p=$6.50

3 0

3 years ago