Answer:
It is general knowledge
Explanation:
What you covered is general knowledge and the entrance to computer science.
Answer:
There is no value of the number variable, for which the loop can be true in any iteration.
Explanation:
- The above loop states the condition that the value should be less than 100 and greater than 500. It is because the loop holds the and condition which gives the true if both conditions will be true.
- The first condition of the while loop states that the value of the number variable is less than the 100.
- The second condition of the while loop state that the value of the number variable is greater than the 500.
- The and condition of the while loop will true if both conditions will true.
- But there is no number which is less than 100 and greater than 500.
- So no number can satisfy the while condition to be true.
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
Answer:
black for font...
and
white for bg color
Explanation:
i think this is enough for ur question...
