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elixir [45]
3 years ago
9

Suppose the interval ​[negative 3−3​,negative 1−1​] is partitioned into nequals=44 subintervals. What is the subinterval length

Upper Delta xΔx​? List the grid points x0​, x1​, x2​, x3​, x4. Which points are used for the​ left, right, and midpoint Riemann​ sums?
Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Answer: Δx​ = 0.5

Step-by-step explanation:

We have the interval:

​[−3​, −1​]

and we partition it into 4 equal intervals.

first, the range of our interval is equal to the difference between the extremes, this is:

-1 - (-3) = -1 + 3 = 2

Then, if we divide it into 4, we have 4 segments with a range of:

2/4 = 0.5

Then the subinterval delta is 0.5, and the 4 intervals are:

​[−3​, -2.5​],  ​[−2.5, −2​],  ​[−2​, −1.5​],  ​[−1.5, −1​]

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Write ninety-eight and one tenth as a decimal number.
deff fn [24]

Answer:

98.1

Step-by-step explanation:

one tenth equates to 0.1

Therefore the answer is 98+0.1=98.1

4 0
3 years ago
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The 2 pentagons above are similar. What is the area of the smaller pentagon?
Anna71 [15]
The correct answer is the third option, which is:

 6 inches²

 The explanation is shown below:

 1. You are working with the areas of the pentagons shown in the figure above. Therefore, the ratios are:

 side1²/side2²=A1/A2

 (7.5)²/(2.5)²=54/A2

 Where A2 is the the area of the smaller pentagon.

 2. Therefore, you have that the result is:

 A2=6 inches² (As you can see, it is the third option mentioned above). 
6 0
3 years ago
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Find the lengths of the diagonals of rectangle QRST, if QS=14x+10 and RT=11x+22.
ehidna [41]

Answer:4

Step-by-step explanation:

diagonals of a rectangle are equal therefore QS=RT, 14x+10=11x+22, and solve for x to get 3x=12, so x equals 4

5 0
3 years ago
For a hyperbolic mirror the two foci are 42 cm apart. The distance of the vertex from one focus is 6 cm and from the other focus
navik [9.2K]

Answer:

\dfrac{y^2}{225} -\dfrac{x^2}{216}=1

Step-by-step explanation:

For a hyperbolic mirror the two foci are 42 cm apart.

The distance between the foci = 2c.

Therefore:

  • 2c=42
  • c=21

The distance of the vertex from one focus = 6 cm

The distance of the vertex from the other focus = 36 cm

2a=36-6=30

  • a=15

Now:

c^2=a^2+b^2\\21^2=15^2+b^2\\b^2=21^2-15^2\\b^2=216\\b=6\sqrt{6}

If the transverse axis lies on the y-axis, and the hyperbola is centered at the origin. Then the hyperbola has an equation of the form:

\dfrac{y^2}{a^2} -\dfrac{x^2}{b^2}=1

Therefore, the equation of the hyperbola is:

\dfrac{y^2}{225} -\dfrac{x^2}{216}=1

4 0
4 years ago
Find a counterexample for the conjecture: If n is a real number, then -n is a negative
kiruha [24]

Answer:

Step-by-step explanation:

-5 is a real number, right ?

- (-5) = 5 is not negative

thanks

6 0
3 years ago
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