Answer:
6.8%
Step-by-step explanation:
the question has no information about class size (no. of student in class)
assume no. of student is infinite
P(3brown out of 6) = 6C3 * P(brown)^3 * P(not brown)^3
= 20 * 0.004913 * 0.695789
= 0.06837
Remember that percent means parts out of 100
x/100
discount is the decrease
so we divide the decrease by the original total and get
100/5775=0.0173
convert to fraction
0.0173/1
make bottom number 100
multiply by 100/100
1.73/100=1.73%
round
2%

Here's the solution ~




Therefore, the correct choice is A
Answer:
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
This is 1 subtracted by the pvalue of Z when X = 9.08. So



has a pvalue of 0.7823
1 - 0.7823 = 0.2177
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Answer:
C = 14d + 3
Step-by-step explanation:
i took the test hope this helps
could you put me as the brainlyest