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shtirl [24]
3 years ago
11

SOMEONE PLZ HELP ASAP !!!!!!

Mathematics
1 answer:
Rasek [7]3 years ago
7 0

Answer:

a = 53.13

b = 42.76

c= 0

Step-by-step explanation:

as the question said i was supposed to use a calculator which i did

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Gables property Corp is leasing office buildings with an area of 49x^2 + 70x +25
Hoochie [10]

Answer:

Given: Gables property Corp is leasing office buildings with an area of 49x^2 + 70x+25

⇒ Area = 49x^2 + 70x+25

we can write this as:

Area = (7x)^2+2\cdot (7x) \cdot (5) + (5)^2            .....[1]

Use the  identity formula:

(a+b)^2 = a^2+2ab +b^2

then, by using this formula in [1] we have;

Area = (7x+5)^2

or

Area = (7x+5)(7x+5) square units

Area of building = l \times w where l is the length and w is the width respectively;

⇒ l = w = 7x+5 units

Therefore, the possible length and width of the building is;

l = 7x+5 units

w = 7x+5 units

As we know that the Area of a square is equal to side times side . Since each side of a square is the same, it can simply be the length of one side squared.

Therefore, the possible shape of the building is Square.



7 0
3 years ago
Can somone give me the answer to 2 x 0
marshall27 [118]
Any number times 0 is going to equal 0
8 0
3 years ago
Read 2 more answers
Which of these is the algebraic expression for some number to the power five
DochEvi [55]

Answer:

x^5

Step-by-step explanation:

x raised to the power 5 is written as

6 0
4 years ago
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F(x) = x2. What is g(x)?
Anarel [89]

Answer:

i think is is c but I not sure.

Step-by-step explanation:

6 0
2 years ago
Add or subtract. Write the result in the form a+bi
STALIN [3.7K]

Number 1: (-1+2i)+(6-9i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-1+6\right)+\left(2-9\right)i\\=5-7i

Number 2: (3-3i)-(4+7i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(3-4\right)+\left(-3-7\right)i\\Refine\\=-1-10i

Number 3: (-5+2i)+(-2+8i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-5-2\right)+\left(2+8\right)i\\Refine\\=-7+10i

8 0
3 years ago
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