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ankoles [38]
3 years ago
6

The temperature in the desert can

Mathematics
1 answer:
Tanya [424]3 years ago
4 0

Answer:

There is an 144 degree difference.

Step-by-step explanation:

112=(-32)+x

solve like a regular equation which will give you 144

(add 32 to 112)

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Please help me with this problem
andrezito [222]

Answer:

I think it is -2

Step-by-step explanation:

I think but I do not know

6 0
4 years ago
15x²y³z÷3xy² simplify
umka21 [38]

Answer:

5xyz

Step-by-step explanation:

\frac{15x^2y^3z}{3xy^2}

Step 1: Divide the numbers

\frac{15}{3}=5\\\\=\frac{5x^2y^3z}{xy^2}

Step 2: Simplify

\frac{x^2}{x}\\\\= x\\\\=\frac{5xy^3z}{y^2}

Step 3: Simplify

\frac{y^3}{y^2} = y\\\\=5xyz

Therefore, the simplified answer is =5xyz

7 0
3 years ago
Read 2 more answers
What is the surface area of the square pyramid below?
Reika [66]

The surface area of square pyramid is the sum of the area of all its sides.

If l is the slant height and base is s each then surface area of pyramid is given by:

Surface area = s2+2xsx l

From the given figure in the question:

S=6 cm ,l= 8cm.

Substituting these values in surface area formula we have:

Surface area = 62+2x6x8

Surface area = 36+96

Surface area =132cm2

6 0
3 years ago
Greg is practicing for a marathon to start he ran 2 miles around the track he wants to know how many yards this is how many yard
IgorC [24]

Answer:

3520 yards

Step-by-step explanation:

1 mile = 1760 yards

2 miles = 2(1760)=3520 yards

3 0
3 years ago
How to do this question plz answer me step by step plzz plz ​
Iteru [2.4K]

Answer:

£13496.80

Step-by-step explanation:

We can ignore the £ sign for now, that is just units.

If we decrease a number by 4.5%, we will have to find 100-4.5=95.5% of 14132.77.

We can easily do this by setting up a proportion.

\frac{x}{14132.77} = \frac{95.5}{100}

Multiply 14132.77 by 95.5:

14132.77\cdot95.5=1349679.535

Divide by 100:

1349679.535\div100=13496.79535

Rounding this to two decimal places, it simplifies to 13496.80.

Hope this helped!

4 0
3 years ago
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