9514 1404 393
Answer:
91°
Step-by-step explanation:
The similarity statement tells you that angles Q and H are congruent. The measure of angle H is shown as 91°, so that is the measure of angle Q.
m∠Q = 91°
Answer: 
Step-by-step explanation:
The missing figure is attached.
For this exercise it is important to remember that, by definition, the opposite interior angles of an inscribed quadrilateral are supplementary, which means that their sum is 180 degrees.
Based on this, you can identify that the angle D and the angle B are opposite and, therefore, supplementary.
Knowing that, you can write the following equation:

Now you must solve for "x" in order to find its value. This is:

Then:

You know that:

Therefore, since you know the value of "x", you can substitute it into
and then you must evaluate, in order to find the measure of the angle A. This is:

<span><span>
The correct answers are:</span><span>
(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0
</span><span>
Explanation:</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.
Rational Function = g(x) = </span></span>

<span>
Denominator = x = 0
Hence the vertical asymptote is x = 0.
(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:
Given function = g(x) = </span>

<span>
We can write it as:
g(x) = </span>

<span>
If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.
In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
Answer:
The answer is A. 204.7
Step-by-step explanation:
Answer:
44.1 x 10^-2
Step-by-step explanation:
Since one grain
= 7 x 10^-5
6300kg = 7 x 10^-5 x 6300
Put 6300 in standard form
7 x 10^-5 x 6.3 x 10^3
Multiply the whole numbers and add the exponents
7 x 6.3 x 10^-5 + 3
44.1 x 10^-2
There are 44.1 x 10^-2 grains of sand in 6300kg