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madreJ [45]
3 years ago
10

Draw the image of ABCD under dilation using the center P and the scale factor of 1/2.

Mathematics
2 answers:
larisa86 [58]3 years ago
6 0
The image is gonna look like this.

KiRa [710]3 years ago
6 0
It should look like the picture I put in

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The distance between -2 1/2 - (-3)
Ierofanga [76]

The distance between -2 1/2 - (-3)​

-2 1/2 + 3

1/2

______________________

Answer

1/2

3 0
1 year ago
In triangle JKL, m of angle J = 90, m of angle K = 30, and m of angle L = 60. Which of the following statements about triangle J
Jobisdone [24]

Answer:

# Answer B is true ⇒ KL = 2(JL)

# Answer C is true ⇒ JK = √3(JL)

# Answer F is true ⇒ JK = √3/2(KL)

Step-by-step explanation:

* Lets explain the ratio between the sides of the triangle

- In Δ JKL

∵ The measure of angle J is 90°

∴ KL is the hypotenuse

∵ The measure of angle K is 30°

∴ JL is the opposite side to angle 30°

∵ The measure of angle L is 60°

∴ JK is the opposite side to the angle 60°

- There is a fact in the triangle which has angles 30° , 60° , 90°

# The length of the side opposite to the angle of measure 30° is

  half the length of the hypotenuse

∵ KL is the hypotenuse

∵ JL is the opposite side to the angle of measure 30°

∴ JL = 1/2 KL  OR KL = 2 JL

# The length of the side opposite to the angle of measure 60° is

  √3 the length of the opposite side to the angle 30°

∵ JK is the opposite side to the angle of measure 60°

∵ JL is the opposite side to the angle of measure 30°

∴ JK = √3 JL

# The length of the side opposite to the angle of measure 60° is also

  half √3 the length of the hypotenuse

∵ JK is the opposite side to the angle of measure 60°

∵ KL is the hypotenuse

∴ JK = √3/2 KL

- From the relation above

# Answer B is true ⇒ KL = 2(JL)

# Answer C is true ⇒ JK = √3(JL)

# Answer F is true ⇒ JK = √3/2(KL)

6 0
4 years ago
The surface area of a triangular pyramid is 1,936 inches squared. If the dimensions are multiplied by 1/4, what will be the new
rosijanka [135]

Answer:

121 inches squared

Step-by-step explanation:

If the dimensions are multiplied by 1/4, we have that the surface area will by multiplied by (1/4)^2, as the dimensions are in inches and the surface area is in inches squared.

So, If the original surface area is 1936 inches squared, the new surface area will be:

New surface area = 1936 * (1/4)^2 = 1936 / 16 = 121 inches squared.

8 0
3 years ago
Show and explain how replacing one equation by the sum of that equation and a multiple of the other produces a system with the s
My name is Ann [436]
First, let's multiply the first equation by two on the both sides:
<span>8x + 7y = 39         /2
</span>⇒ 16x + 14y = 78

Now, the system is:
<span>16x + 14y = 78
</span><span>4x – 14y = –68
</span>
After adding this up in the column:
(16x + 4x) + (14y - 14y) = 78 - 68
20x = 10
⇒ x = 10/20 = 1/2


y can be calculated by replacin the x:
<span>8x + 7y = 39
</span>⇒ 8 · 1/2 + 7y = 39
4 + 7y = 39
7y = 39 - 4
7y = 35
⇒ y = 35 ÷ 7 = 5
3 0
4 years ago
Read 3 more answers
How to solve for first derivative?? I have two questions, one where I have the answer, however one where I don’t. The format of
rjkz [21]

Answer:

Q1: f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

Q2: f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

Step-by-step explanation:

The derivative of the product of two functions is:

f(x) = v(x)u(x)

f'(x) = v(x)u'(x) + u(x)v'x)

The derivative is the product of the first function and the derivative of the second function added to the product of the second function and the derivative of the first function.

Q1: The function you are given is:

f(x) = 6x^8(-6x^8 + 2x^4 + 4)

You can think of that function as the product of functions

u(x) = 6x^8 and v(x) = -6x^8 + 2x^4 + 4

We first find the derivatives of functions u and v:

u'(x) = 48x^7 and v'(x) = -48x^7 + 8x^3

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^8)(-48x^7 + 8x^3) + (-6x^8 + 2x^4 + 4)(48x^7)

Use the commutative property to change the order of the sum.

f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

This is the solution you have.

Q2: The function you are given is:

f(x) = 6x^4(6x^3 - 6x^9 + 3)

You can think of that function as the product of functions

u(x) = 6x^4 and v(x) = 6x^3 - 6x^9 + 3

We first find the derivatives of functions u and v:

u'(x) = 24x^3 and v'(x) = 18x^2 - 54x^8

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

5 0
3 years ago
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