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NeTakaya
3 years ago
15

The surface area of a triangular pyramid is 1,936 inches squared. If the dimensions are multiplied by 1/4, what will be the new

surface area?
Mathematics
1 answer:
rosijanka [135]3 years ago
8 0

Answer:

121 inches squared

Step-by-step explanation:

If the dimensions are multiplied by 1/4, we have that the surface area will by multiplied by (1/4)^2, as the dimensions are in inches and the surface area is in inches squared.

So, If the original surface area is 1936 inches squared, the new surface area will be:

New surface area = 1936 * (1/4)^2 = 1936 / 16 = 121 inches squared.

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On a spelling test, Marcy got 15% of the questions incorrect. If there were 40 questions on the spelling test, than how many que
marissa [1.9K]

Answer:

34

Step-by-step explanation:

Marcy got 15% of the 40 wrong

.15 *40

6

If she got 6 wrong, then she got the rest right

40-6 = 34

She got 34 right

4 0
3 years ago
PLEASE HURRY!!!!
Pavel [41]

Answer:

D

Step-by-step explanation:

You are going to roll two dice.

If you roll one die, then there are 6 possible outcomes: 1, 2,  3, 4, 5, 6

If you roll two dice, then there are 6\times 6=36 possible outcomes:

\begin{array}{cccccc}1-1&1-2&1-3&1-4&1-5&1-6\\ \\2-1&2-2&2-3&2-4&2-5&2-6\\ \\3-1&3-2&3-3&3-4&3-5&3-6\\ \\4-1&4-2&4-3&4-4&4-5&4-6\\ \\5-1&5-2&5-3&5-4&5-5&5-6\\ \\6-1&6-2&6-3&6-4&6-5&6-6\end{array}

Here the first number is the number rolled on the first die, the second number is the number rolled on the second die.

5 0
4 years ago
Read 2 more answers
; the boy to girl ratio is 10 to 8. If there are 16 girls in the class, how many boys are there?​
Zigmanuir [339]

Answer:

There are 20 boys

Step-by-step explanation:

4 0
3 years ago
En un huerto se siembra frijol. Si se pone una planta, produce 3kg de frijol. por cada planta extra que se ponga, todas las plan
Ad libitum [116K]

Answer:

y = -0.07x2 + 3.07x

Step-by-step explanation:

For each plant we add, there is a decrease of 70 grams for all plants from the inicial value of 3 kg of beans.

So, for 2 plants, we have (3 - 0.07) * 2

For 3 plants, we have (3 - 2*0.07) * 3

For x plants, we have (3 - (x-1)*0.07) * x

So we can model the final result of the amount of beans 'y' with the equation:

y = (3 - (x-1)*0.07) * x

y = (3 - 0.07x + 0.07) * x

y = (3.07 - 0.07x) * x

y = -0.07x2 + 3.07x

(In this equation we have a = -0.07, b = 3.07 and c = 0)

7 0
3 years ago
How do I solve this​
Alina [70]

\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\displaystyle\sum \limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio} \end{cases} \\\\[-0.35em] ~\dotfill

\bf S_{20}=\displaystyle\sum \limits_{n=1}^{\stackrel{\stackrel{n}{\downarrow }}{20}}~\stackrel{\stackrel{a_1}{\downarrow }}{3}(\stackrel{\stackrel{r}{\downarrow }}{1.5})^{n-1}\implies S_{20}=3\left(\cfrac{1-1.5^{20}}{1-1.5} \right)\implies S_{20}=3\left(\cfrac{1-\stackrel{\approx}{3325.3}}{-0.5} \right) \\\\\\ S_{20}=3\left(\cfrac{-3324.3}{-0.5} \right)\implies S_{20}=3(6648.6)\implies S_{20}=19945.8

8 0
3 years ago
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