All categories

4 years ago

In the computer lab, there are 14 Apple computers and 16 PC computers. Approximately what percent of the computers are PC?

Mathematics

2 answers:

Minchanka [31]4 years ago

8 0

Answer:

53%

Step-by-step explanation:

In the computer lab, there are 14 Apple computers and 16 PC computers. There are total of 16+14 computers = 30 computers.

16/30 multiplied by 100

= 53% in approximation.

53% of the computers are PC, while the rest 47% are Apple's.

gulaghasi [49]4 years ago

8 0

Add 14 + 16= 30. That is your denominator
16 / 30 = 53 percent

You might be interested in

I urgently need help!!!!!!

kifflom [539]

Answer:

try C if not then A B or D

Step-by-step explanation:

7 0

3 years ago

what is range of the inverse of the relation {(1, 7), (-2, 4), (5, 6), (2, 8)} A. {1, 2,5} B. {-4, 6, 7, 8} C. {1, 5} D. {-4, 7,

Rufina [12.5K]

The answer should be the domain of this relation. {-2, 1, 2, 5} but I do not see that as one of your answer choices.

The inverse of a relation is when you switch the domain and range. In other words, the domain of the original relation becomes the range of the inverse.

8 0

3 years ago

Find the indefinite integral by using the substitution x = 4 sec(θ). (Use C for the constant of integration.) x2 − 16 x d

guapka [62]

Answer:

$\frac{x^2-16}{2} + 16ln\frac{4}{x} +16C$

Step-by-step explanation:

Given the indefinite integral $\int\limits{\frac{x^2-16}{x} } \, dx$ , using the substitute

x = 4 sec(θ)...1

The integral can be calculated as thus;

First let us diffrentiate the substitute function with respect to θ

dx/dθ = 4secθtanθ

dx = 4secθtanθdθ... 2

Substituting equation 1 and 2 into the integral function we will have;

$\int\limits{\frac{(4sec \theta)^2-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{16sec^2 \theta-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{(16(sec^2 \theta-1)}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\from \ trig \ identity,\ sec^2 \theta - 1 = tan^\theta\\\\\int\limits{\frac{16 tan^2 \theta}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\\int\limits 16 tan^3 \theta d \theta\\\\$

Find the remaining solution in the attachment.

3 0

3 years ago

The weight of meteorite A is 5 times the weight of meteorite B. If the sum of their weights is 126 tons, find the weight of each

Sholpan [36]

Answer:

Step-by-step explanation:

if you divide 126 by 5, you get Meteorite B, 25.2, then minus that from 132, and you get Meteorite A, 106.8

To check, do 25.2 x 5 and you should get 132.

5 0

3 years ago

A jacket is advertised to be 85% off the original price. If the sale price is $102 what is the original price ?

Jobisdone [24]

The answer would prob around $188.70 because .85x102=86.7 so add that to 102 and u get 188.70 but I'm prob wrong and I have a test on this tomorrow

<span />

4 0

3 years ago