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nevsk [136]
3 years ago
11

Putting soil is sold in bags that contain 1/2 cubic foot of soil. Estimate how many bags Rylee should buy.

Mathematics
2 answers:
kap26 [50]3 years ago
8 0

Answer:

Ok. So, I can't see the image. Buttttt, depending on how many cubic feet she wants. If she wanted 5.5 cubic feet of soil, she would buy 10 bags of soil. Each showing 1/2 of a cubic foot. Use your fingers to help saying, " Half, One, One and a half, two, two and a half...." So on and so forth.

Step-by-step explanation:

fredd [130]3 years ago
8 0

9514 1404 393

Answer:

  11 bags

Step-by-step explanation:

12. As you noted in problem 11, the volume needed to fill the three pots is 5.05 cubic feet. The number of bags needed is ...

  (5.05 ft³)/(0.5 ft³/bag) = 10.1 bags

10 bags is not quite enough. Rylee should buy 11 bags of potting soil.

_____

<em>Additional comment</em>

As a practical matter, the difference between what Rylee needs and what is contained in 10 bags is about 1%. It would be very difficult to tell that 0.1 cubic foot is missing if Rylee simply used the contents of 10 bags. If Rylee purchases 11 bags, most (4/5) of the last bag will remain unused.

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3 years ago
A leaking bucket is filled to 3/4 capacity. After some time, 1/2 of the water has leaked out. What fraction of the water leaked
Ilia_Sergeevich [38]
C. 3/8 is the answer
3 0
3 years ago
If y varies inversely asx, and y = 33 when x = 7 what is the constant and what is value of y when x=11?
allsm [11]

Answer:

We have that y = 21 when x = 11.

Step-by-step explanation:

We solve this question by proportions, using a rule of three.

Since they vary inversely, we apply the inverse rule of three, that is, with lateral multiplication instead of diagonal.

33 - 7

y - 11

So

11y = 33 -7

y - 11

Dividing both sides by 11

Y = 3 * 7 = 21

We have that y = 21 when x = 11.

7 0
3 years ago
Solve the equation x+3/x-4 = x-5/x+4
Serga [27]

Answer:

\large\boxed{x=\dfrac{1}{2}}

Step-by-step explanation:

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\\\\\text{Domain:}\ x-4\neq0\ \wedge\ x+4\neq0\\\\x\neq4\ \wedge\ x\neq-4\\\\D:x\in\mathbb{R}-\{-4,\ 4\}

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\qquad\text{cross multiply}\\\\(x+3)(x+4)=(x-4)(x-5)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x)(x)+(x)(4)+(3)(x)+(3)(4)=(x)(x)+(x)(-5)+(-4)(x)+(-4)(-5)\\\\x^2+4x+3x+12=x^2-5x-4x+20\qquad\text{combine like terms}\\\\x^2+(4x+3x)+12=x^2+(-5x-4x)+20\\\\x^2+7x+12=x^2-9x+20\qquad\text{subtract}\ x^2\ \text{from both sides}\\\\7x+12=-9x+20\qquad\text{subtract 12 from both sides}\\\\7x=-9x+8\qquad\text{add}\ 9x\ \text{to both sides}\\\\16x=8\qquad\text{divide both sides by 16}\\\\x=\dfrac{8}{16}\\\\x=\dfrac{8:8}{16:8}\\\\x=\dfrac{1}{2}\in D

7 0
3 years ago
How do i find the greatest common factor of 84 and 36
Rufina [12.5K]

Answer:

What is the GCF of 36 and 84?

Find the prime factorization of 36.

Find the prime factorization of 84. 84 = 2 × 2 × 3 × 7.

To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 2 × 2 × 3.

GCF = 12.

The common factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, and 84. We can get all the factors using the prime factorization method.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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