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3 years ago

Putting soil is sold in bags that contain 1/2 cubic foot of soil. Estimate how many bags Rylee should buy.

Mathematics

2 answers:

kap26 [50]3 years ago

8 0

Answer:

Ok. So, I can't see the image. Buttttt, depending on how many cubic feet she wants. If she wanted 5.5 cubic feet of soil, she would buy 10 bags of soil. Each showing 1/2 of a cubic foot. Use your fingers to help saying, " Half, One, One and a half, two, two and a half...." So on and so forth.

Step-by-step explanation:

fredd [130]3 years ago

8 0

9514 1404 393

Answer:

11 bags

Step-by-step explanation:

12. As you noted in problem 11, the volume needed to fill the three pots is 5.05 cubic feet. The number of bags needed is ...

(5.05 ft³)/(0.5 ft³/bag) = 10.1 bags

10 bags is not quite enough. Rylee should buy 11 bags of potting soil.

_____

Additional comment

As a practical matter, the difference between what Rylee needs and what is contained in 10 bags is about 1%. It would be very difficult to tell that 0.1 cubic foot is missing if Rylee simply used the contents of 10 bags. If Rylee purchases 11 bags, most (4/5) of the last bag will remain unused.

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What is the preimeter of a haxagon that has equal sides of 12 inches?

lidiya [134]

Answer:

72 inches because a hexagon has 6 sides so you multiply 6 × 12

3 0

3 years ago

Read 2 more answers

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

The point $(1\frac{1}{2},1)$ won't be on the graph because the corresponding value of y for $x = 1\frac{1}{2}$ is $y = 2\frac{1}{4}$

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

The point $(4,6)$ would be on the graph because the corresponding value of y for $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

The point $(18,12)$ wouldn't be on the graph because the corresponding value of y for $x = 18$ is $y = 12$

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

The point $(0,0)$ would be on the graph because the corresponding value of y for $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

The point $(2\frac{1}{2},3\frac{3}{4})$ would be on the graph because the corresponding value of y for $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

3 years ago

Question 1 (1 point)

olya-2409 [2.1K]

For this case we can propose a system of equations:

x: Let the variable that represents the number of small cookies

y: Let the variable that represents the number of large cookies

According to the statement we have:

$x + y = 130\\2x + 3y = 310$