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3 years ago

What percent 21 is of 25

Mathematics

1 answer:

kvv77 [185]3 years ago

3 0

Answer:

The answer is 84

Step-by-step explanation:

convert 21 from 25 into a decimal to get 84

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2y-18x=-26 solve for y

Alekssandra [29.7K]

2y - 18x = -26

Add 18x to both sides.

2y = -26 + 18x

Divide by 2 on both sides.

y = -13 + 9x

y = 9x - 13

8 0

3 years ago

PLEASE HELP

a_sh-v [17]

Answer:

x = 8 and y = - 1

Step-by-step explanation:

The equation of a vertical line parallel to the y- axis is

x = c

where c is the value of the x- coordinates the line passes through

The line passes through (8, - 1 ) with x- coordinate 8, then

x = 8 ← equation of vertical line

The equation of a horizontal line parallel to the x- axis is

y = c

where c is the value of the y- coordinates the line passes through

The line passes through (8, - 1 ) with y- coordinate - 1, then

y = - 1 ← equation of horizontal line

7 0

2 years ago

a tree casts a shadow 42 feet long.at the same time, a person 5 feet tall casts a shadow 7 feet long. what is the hight of the t

arlik [135]

Answer:

height of the tree is 30 feet

Step-by-step explanation:

a tree casts a shadow 42 feet long . at the same time, a person 5 feet tall casts a shadow 7 feet long.

shadow of a 5 feet tall person is 7 feet long

Let x be the height of the tree

shadow of a 42 feet tree is x feet long

Make a proportion

$\frac{x}{42} =\frac{5}{7}$

cross multiply

$7x=(42)(5)$

$7x=210$

divide by 7 on both sides

x=30

So height of the tree is 30 feet

4 0

3 years ago

What does the fundamental theorem of algebra illustrate?

UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form $ax^{2}+bx +c=0$

Its roots are $\frac{-b+\sqrt{b^{2}-4ac } }{2a}$ and $\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Here the given equation is $2x^{2}-4x-1$ = 0

a = 2

b = -4

c = -1

If the roots are $x_{1} and x_{2}$ , then

$x_{1}$ = $\frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{24}}{4}$

= $\frac{2+\sqrt{6} }{2}$

$x_{2}$ = $\frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{8}}{4}$

= $\frac{2-\sqrt{6} }{2}$

These are the two roots of the equation.

6 0

3 years ago

Ch.3 Test Savings Accounts

Harlamova29_29 [7]

Step-by-step explanation:

5000 x 3 + 3.5% of 5000 x 3 = the answer

8 0

3 years ago