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enot [183]
3 years ago
12

What is the solution of the system?

Mathematics
2 answers:
damaskus [11]3 years ago
7 0
3x +2y= 11 ----1
x -2 = -4y   ---- 2

Equation 2 times by 3
3x -6 = -12y

Subracting 2-1
3x-6=-12y
3x-11=-2y

Leaving 
5=-10y
y= -1/2

Hence 
B. is the solution

PS, If you rate this as "Brainiest" that would be most appreciated

Rama09 [41]3 years ago
3 0
X - 2 = -4y
x = -4y + 2
Now, substitute the value of x in first equation, 
3(-4y+2) + 2y = 11
-12y + 6 + 2y = 11
-10y = 5
y = -1/2

Now, substitute the value of y in 2nd equation, 
x = -4(-1/2) + 2
x = 2 + 2 = 4

In short, Your Answers are x = 4 and y = -1/2, Which is Option B

Hope this helps!
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If <img src="https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B2y%7D%7Ba%7D%20" id="TexFormula1" title=" x = \frac{2y}{a} " alt=" x
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\bf A) \\\\\\ \cfrac{3\left( \frac{2y}{a} \right)}{y}\implies \cfrac{\frac{6y}{a}}{y}\implies \cfrac{6y}{a}\cdot \cfrac{1}{y}\implies \cfrac{6}{a}\quad \otimes \\\\\\ B) \\\\\\ \cfrac{6\left( \frac{2y}{a} \right)}{y}\implies\cfrac{\frac{12y}{a}}{y}\implies \cfrac{12y}{a}\cdot \cfrac{1}{y}\implies \cfrac{12}{a}\quad \otimes \\\\\\ C) \\\\\\ \cfrac{6y}{\left( \frac{2y}{a} \right)}\implies \cfrac{6y}{1}\cdot \cfrac{a}{2y}\implies 3a\quad \otimes

\bf D) \\\\\\ \cfrac{12\left( \frac{2y}{a} \right)}{y}\implies \cfrac{\frac{24y}{a}}{y}\implies \cfrac{24y}{a}\cdot \cfrac{1}{y}\implies \cfrac{24}{a}\quad \otimes \\\\\\ E) \\\\\\ \cfrac{12y}{\left( \frac{2y}{a} \right)}\implies \cfrac{12y}{1}\cdot \cfrac{a}{2y}\implies 6a\quad \checkmark

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