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enot [183]
3 years ago
12

What is the solution of the system?

Mathematics
2 answers:
damaskus [11]3 years ago
7 0
3x +2y= 11 ----1
x -2 = -4y   ---- 2

Equation 2 times by 3
3x -6 = -12y

Subracting 2-1
3x-6=-12y
3x-11=-2y

Leaving 
5=-10y
y= -1/2

Hence 
B. is the solution

PS, If you rate this as "Brainiest" that would be most appreciated

Rama09 [41]3 years ago
3 0
X - 2 = -4y
x = -4y + 2
Now, substitute the value of x in first equation, 
3(-4y+2) + 2y = 11
-12y + 6 + 2y = 11
-10y = 5
y = -1/2

Now, substitute the value of y in 2nd equation, 
x = -4(-1/2) + 2
x = 2 + 2 = 4

In short, Your Answers are x = 4 and y = -1/2, Which is Option B

Hope this helps!
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LekaFEV [45]
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4x = width
324 = perimeter
formula: P = 2(length) + 2(width)

324 = 2(5x) + 2(4x)
324 = 10x + 8x
324 = 18x
18 = x
Substitute the value of x = 18
Length = 5x = 5(18) = 90meters
Width = 4x = 4(18) = 72meters
5 0
3 years ago
PLEASE HURRY I HAVE A TIME LIMIT
Softa [21]

Answer:

CAB = 30.71   BCA = 90    ABC = 59.29

Step-by-step explanation:

BCA = 90

9x + 6 + 5x = 90

14 x = 90-6 = 84

x = 43/7

(43/7 ) * 5 = 30.71

90 - 30.71 = 59.29

6 0
3 years ago
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3 0
3 years ago
38600 mg = n dag what does n equal???
Vlad [161]
Answer:
n = 3.68

Explanation:
We know that:
1 mg is equivalent to 0.0001 dag
To convert 38600 mg to dag, we will simply use cross multiplication as follows:
1 mg ..............> 0.0001 dag
38600 mg ......> n

n = (38600*0.0001) / 1
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Hope this helps :)
3 0
3 years ago
What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
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