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3 years ago

Please help me ASAP

Mathematics

1 answer:

expeople1 [14]3 years ago

7 0

Your equation would be:

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a rectangular prism has a square base with a side length of 10 inches. The volume of the prism is 1,600 cubic inches. Find the s

Liula [17]

Answer:

840 in^2

Step-by-step explanation:

If the base is square and the side length is 10 inches, the areas of the base and of the top combined is 2(100 in^2).

The height of the prism comes from dividing the volume, 1600 in^3, by the area of the base, 100 in^2: It is 16 in. Then the combined areas of the four sides of the prism is 4(160 in^2).

The total surface area of the prsim is then 640 in^2 + 200 in^2, or 840 in^2.

7 0

2 years ago

What is the best approximation for the circumference of a circle with a radius of 125 m?

ANEK [815]

Answer:

Option B is correct

circumference of a circle is 785 m

Step-by-step explanation:

Circumference of the circle(C) is given by:

$C = 2\pi r$

where

r is the radius of the circle

As per the statement:

radius of the circle is 125 m

then substitute in [1] we have

$C = 2 \cdot 3.14 \cdot 125$

Simplify:

C = 785 m

Therefore, the circumference of a circle is 785 m

8 0

3 years ago

Read 2 more answers

PLEASE HELP

Fantom [35]

In step 3, Mark forgot to multiply 5 · 5, so he ended up with 5 in the denominator instead of 5 · 5 = 25

3 0

3 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

3 years ago

Find each Unit rate:

raketka [301]

The unit rate is 2.5 meters in 1 second

40/16=2.5

5 0

3 years ago

Read 2 more answers