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2 years ago

11

If 10 centimeters equal 1 decimeter and it takes 8dm of shipping paper to wrap a large package. How many cm of paper would be ne

eded?

1 answer:

motikmotik2 years ago

8 0

The answer would be 80cm

All you have to do is multiply 10×8 to get the answer

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A polynomial has one root that equals 5-7i. Name one other root of this polynomial

mezya [45]

Answer:

The other root is 5 + 7i.

4 0

3 years ago

Read 2 more answers

For a normal distribution,

Anni [7]

Answer:

1.282, -0.5244,...

Step-by-step explanation:

We know that Z is a standard normal variate with mean =0, and std dev =1

a) z-score separates the highest 10% from the rest of the scores

= 90th percentile = 1.282

b) z-score separates the lowest 30% from the rest of the scores

= 30th percentile = -0.5244

c) z-score separates the lowest 40% from the rest of the scores

= 40th percentile = -0.2533

d) z-score separates the lowest 20% from the rest of the score

=20th percentile = -0.8416

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2 years ago

A shopper bought a 12-pound bag of oranges for 18.75. What is the unit price per ounce?

noname [10]

Answer:

About $0.10 per ounce

Step-by-step explanation:

12 pound costs $18.75. Lets find the cost per pound first:

Cost Per Pound = $\frac{18.75}{12}=1.5625$

We know, there are 16 ounces in 1 pound.

We know 1 pound costs 1.5625

To find cost per ounce, we have to divide this by 16.

So,

Cost Per Ounce = $\frac{1.5625}{16}=0.097$

Rounded to nearest cent, that would be 10 cents per ounce

5 0

3 years ago

What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)

dedylja [7]

<u>Answer:</u>

32 units

<u>Step-by-step explanation:</u>

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

B (-3,0)

C (1,0)

D (1,-6)

AB = $\sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100}$ = 10 units

BC = $\sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16}$ = 4 units

CD = $\sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36}$ = 6 units

AD = $\sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144}$ = 12 units

Perimeter of ABCD = $10+4+6+12$ = 32 units

6 0

3 years ago

What values must x have so that log (x) is greater than 2? justify your answer

kotegsom [21]

Answer:

The value of x must be greater than 100.

Step-by-step explanation:

We need to find the value x for which the value of log(x) is greater than than 2.

$log(x)>2$

According to the property of logarithm, if a is a real number.

$log(x)=a \Rightarrow x=10^a$

Using the above property of logarithm, the given inequality can be rewritten as

$x>10^2$

$x>100$

We conclude that the value of log(x) is greater than 2 for real values of x which are greater than 100.

Therefore, the value of x must be greater than 100.

3 0

3 years ago