Question

Plz help I'll give brainlest

Answer 1

1.Area of the parallelogram= 288 square units

2.Area of the parallelogram=45 $m^2$

3.Area of the trapezoid   = 34 square in.

4.Area of the trapezoid = 8 square ft

5.Area of the rhombus= 27 square cm

6.Area of the rhombus= 108 square in

7.The area of the desktop is  = 1200 square in

8.The area of the rhombus is =84 $cm^2$

9.Area of the trapezoid  = 240 square ft

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) $m^2$

                                         =45 $m^2$

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =$\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

                            $=\frac{1}{2} \times (12+5) \times 4$ square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =$\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

                              $=\frac{1}{2} \times (2+6) \times 2$ square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

                               $=\frac{1}{2 } \times 6\times 9$ square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

                               $=\frac{1}{2 } \times 12\times 18$ square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = $\frac {1}{2} \times 14 \times 12$ $cm^2$

                                         =84 $cm^2$

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =$\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

                                    = $\frac{1}{2} \times (24+16) \times 12$ square ft

                                     = 240 square ft