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wariber [46]
3 years ago
9

Find the exact value of the expression. Sin 265 cos 25 - cos 265 sin 25

Mathematics
1 answer:
DerKrebs [107]3 years ago
4 0
Answer:

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=-\frac{\sqrt{3}}{2}

Step-by-step explanation:

Recall that;

\sin(A) \cos(B)-\sin(B) \cos(A)=\sin(A-B)

This implies that;

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=\sin(265\degree-25\degree)

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=\sin(240\degree)

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=\sin(180\degree+60\degree)

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=-\sin(60\degree)

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=-\frac{\sqrt{3}}{2}
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URGENT! if ABCD is dilated by a factor of 2, the coordinate of A' would be:
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After dilating the quadrilateral ABCD by a factor of 2 and with respect to the origin, the point A(x, y) = (-3, -1) is transformed into the point A'(x, y) = (-9, -3).

<h3>How to determine the coordinates of an image after applying a rigid transformation</h3>

First of all, dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied on <em>geometric</em> loci such that the <em>Euclidean</em> distance at every point of the construction is conserved. Vectorially speaking, the dilation is expressed by the following formula:

A'(x, y) = A(x, y) + k · [A(x, y) - O(x, y)]     (1)

Where:

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If we know that A(x, y) = (-3, -1), k = 2 and O(x, y) = (0, 0), then the coordinates of A' are:

A'(x, y) = (-3, -1) + 2 · [(-3, -1) - (0, 0)]

A'(x, y) = (-3, -1) + (-6, -2)

A'(x, y) = (-9, -3)

After dilating the quadrilateral ABCD by a factor of 2 and with respect to the origin, the point A(x, y) = (-3, -1) is transformed into the point A'(x, y) = (-9, -3).

To learn more on dilations: brainly.com/question/13176891

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