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Anika [276]
2 years ago
11

X is all of the following except. a constant a varlable an expression

Mathematics
2 answers:
diamong [38]2 years ago
8 0

Answer:

A constant

Step-by-step explanation:

DanielleElmas [232]2 years ago
6 0

Answer:

a constant

Step-by-step explanation:

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Evaluate using integration by parts ​
PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

I(n)=\displaystyle\int x^ne^x\,\mathrm dx

One round of IBP, setting

u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx

\mathrm dv=e^x\,\mathrm dx\implies v=e^x

gives

\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx

I(n)=x^ne^x-nI(n-1)

This is called a power-reduction formula. We could try solving for I(n) explicitly, but no need. n=5 is small enough to just expand I(5) as much as we need to.

I(5)=x^5e^x-5I(4)

I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)

I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)

I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)

I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))

Finally,

I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C

so we end up with

I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C

I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C

and the antiderivative is

\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C

8 0
2 years ago
I need help<br> What is -8.6 divide (-3)
Hitman42 [59]
2.86 the negatives will cancel it self den u divide it
8 0
2 years ago
Ted likes to run long distances. He can run 20 km 95 minutes. He wants to know how many kilometers (k) he will go if he runs at
maxonik [38]

He will run 60km in 285 minutes.



8 0
3 years ago
Read 2 more answers
Name the ordered pairs for the vertices on the figure below
Elanso [62]

Answer:

where is the figure?

Step-by-step explanation:

4 0
3 years ago
A catering company charges $300 plus $40 per guest for a wedding. Sarah and Eric do not want to spend more than $5,000 on cateri
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Y=300+40g
Y=5000
5000=300+40g
-300
4700=40g/40
117.5=g
About 117 people without going over budget.
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3 years ago
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