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BARSIC [14]
3 years ago
6

This is very confusing need help

Mathematics
1 answer:
nalin [4]3 years ago
4 0
A: +
B: 0
C: -
D: Undefined
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Ostrovityanka [42]
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8 0
3 years ago
What is the area of the poster board that she has left
steposvetlana [31]
Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.

Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2

Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2

Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2

ANSWER: 155 in^2 is the area of the poster board she has left.

Hope this helps! :)
5 0
3 years ago
Given p (a) = 0.45, p (b) = 0.30, p (a ∩<br> b.= 0.05. find p (a|b).
Mice21 [21]
Use the conditional probability formula, P(a|b) = P(a and b)/P(b)
7 0
3 years ago
F(x) = -x^2 + 5x – 2<br> Find f(-4)
disa [49]

Answer:

2

Step-by-step explanation:

if f(4), than -4^2=-16

5(4)=20

-16+20-2=2

8 0
3 years ago
What is the probability of drawing two blue marbles if the first one is placed back in the bag before the second draw
Ilia_Sergeevich [38]
Break it down into two parts. First, what is the probability of drawing a blue marble on the first draw?Since there are 5 blue marbles and 10 total, the probability is 5⁄10, or 1/2. Now since we no longer have that blue marble, there are 4 blue marbles and 9 total. The chances of drawing a blue marble are 4/9. Therefore, the chance that both marbles drawn are blue is the chance that the first one is blue times the chance that the second one is blue. 1/2 * 4/9 = 4/18 = 2/9 Remember, math is always trying to trick you. It wants you to try and do the whole big problem at once, which can be difficult. Break it down into smaller problems, then use your answers to small parts to find the answer to the big question. Hope that helps,
7 0
4 years ago
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