Given:

Uniform distribution of length of classes between 45.0 to 55.0 minutes.

To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:

45+55/2 = 50

So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />

3 0

2 years ago

What is 9999999999999999999999999999999×99999999999999999999999991112

Neko [114]

1e+60
Is the answer because it just becomes another problom as you do the math

3 0

3 years ago

at a parade, 1/4 of the participants have red hair, 1/6 of them have brown hair and the rest of them have black hair. which frac

netineya [11]

$\frac{1}{1}-\ all\ participants\\\\
\frac{1}{4}-\ participants\ with\ red\ hair\\\\ \frac{1}{6}-\ participants\ with\ brown\ hair\\\\
participants\ ith\ black\ hair=1-\frac{1}{4}-\frac{1}{6}\ \ \ | mu;tiply\ by\ 12\\\\
12participants\ ith\ black\ hair=12-3-2\\\\
12participants\ ith\ black\ hair=7\ \ \ \ | divide\ by\ 12\\\\
participants\ ith\ black\ hair=\frac{7}{12}$

6 0

3 years ago

A store sells a certain tile for $2 per tile and a pint of paint for $3. A second store sells the same items for $1 per tile and

Paladinen [302]

2t + 3p = 26
t + 4p = 18

8 0

3 years ago

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